300 mm 30 kN/m 50 mm 40 kN c 50 mm A 350 mm 4 m 2 m 2 m 50 mm 200 mm a. Draw the shear diagram of the beam. b. Draw the moment diagram of the beam. c. What is the magnitude of the maximum moment? d. What is the maximum flexural stress acting on the beam? e. Draw the flexural stress diagram of the beam. f. What is the magnitude of the maximum shear? g. What is the maximum shear stress acting on the beam? h. Draw the shear stress diagram of the beam. i. Determine the maximum deflection if E = 8 GPa. %3D

The solid shaft shown in the figure below is fixed at one end and has a lever at the other. The shaft is supported by two bearings. A force F of 790 N is applied at the end of the lever, a distance b of 75 mm from the centre line of the shaft. The shaft has an outer diameter of 12 mm. Find the bending stress at point A, on the outer surface of the shaft, a distance a of 80 mm along the shaft from the lever. Give your answer in N/mm² to 3 significant figures. Fixed end Bearing Shaft A a Lever b F

Question 2) In the system given in the figure, a distributed load of w=36 kN/m acts on the rod AB of L=4 m length. The angle θ that the bar BC makes with the horizontal is θ=48°. The allowable normal stress for bar BC is σm= 221 MPa, and the allowable shear stress for pins at points A and B is τm=68 MPa. Bar BC has a rectangular section and the side length a of the section is given as a=34 mm. According to this;Question 2-A) Find the smallest b side length required for the bar section BC. (Write your result in mm.)Question 2-B) The connection type at point B is given in the figure next to it. Accordingly, find the smallest diameter required for pin B. (Write your result in mm.)

The internal shear force V at a certain section of an aluminum beam is 40 kN. The beam's centroid is located 54.40 mm above the bottom surface of the beam, and the moment of inertia is l₂ = 398,300 mm4. Determine the shear stress at point H, which is located 30 mm above the bottom surface of the beam. 30 mm 75 mm y H 5 mm 5 mm 75 mm