3.What is a dislocation? List five more microscopic defects in bulk materials. Which of the following properties are most sensitive to dislocation structures in materials? a. Young's modulus b. Yield strength c. Conductivity d. Transparency
Q: 3 MPa. Which of the following describes the stress state? A body is subjected to the following…
A: in question stress in various plane is given: question is asking about stress state: given: SIGMAxx…
Q: Considering a finite cylinder of single crystal aluminum with a diameter (D) that has an axial unit…
A: The values provided are as follows:- A finite cylinder of single crystal aluminium with a diameter…
Q: Which of the following option does not match? Material Nature Stress-Strain Behaviour a) Elasto -…
A: Elastic: When stress increases with increase in strain is elastic zone of the material. Plastic:…
Q: An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 860 mm.…
A:
Q: The stress in an elastic material is: A Inversely proportional to the force acting B Inversely…
A: Explanation: A) Stress means resistance force per unit area, resistance force means the force acting…
Q: 1 The material deforms considerably even with a slight increase in stress. Yielding b. Fracture a.…
A: The property of material can be explained as follows- Yield point- It is the point in the…
Q: An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 840 mm.…
A:
Q: If the bulk modulus of e
A: P=13.2MPa
Q: The modulus of elasticity are slightly higher for ceramic materials, Polymers have modulus values…
A: Metals, including natural alloys, are composed of metallic components that are connected…
Q: A cylindrical polymer with a diameter of 10nm when stress is applied to it and a change in diameter…
A: Let the applied Force be F in Newton and A is the area of polymer.Area of…
Q: A joint between two glass plates A and B is filled with a flexible epoxy that bonds securely to the…
A:
Q: 8.58 Why are isotactic or syndiotactic polymers often more attractive for materials development?
A: Isotactic polymers are those where all of the functional groups are on the identical side.
Q: A bronze rod is rigidly attached between an aluminum rod and a steel rod as shown in the figure…
A:
Q: A aluminum plate 0.5 cm thick is to withstand a force of 50,000 N with no permanent deformation. If…
A: Given Data: The thickness of the plate is t=0.5 cm The force to be withstand by the plate is F=50000…
Q: For a material having modulus of elasticity E and modulus of rigidity N, it is seen that E = 2 N.…
A: given- modulus of elasticity=Emodulus of rigidity=NE=2N
Q: An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 660 mm.…
A:
Q: An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 680 mm.…
A: FIND NA :y=36×95(952)-22×22(95-7-222)36×95-22×22y=22.637mmFIND MOI…
Q: Explain why the experimental strength of materials are lower than their theoretical strengths.
A:
Q: Compare ceramics to metals and polymers respectively in terms of deformation
A: ceramic metals polymer ceramic materials are brittle in nature i.e, ceramic materials fracture…
Q: In a tensile test a metal begins to neck at a true strain = 0.28 with a corresponding true stress =…
A:
Q: The following figure displays both an Edge Dislocation and a Screw Dislocation. Answer the following…
A: When dislocation occurs , the particles will move with respect to the burgers vector .
Q: A tensile force of 5 kN produce an elastic reduction in diameter of 4 x 10-4 mm on a metal alloy…
A:
Q: Explain how dislocations have paradoxically rationalized why metals can be both mechanically weak…
A: The hardening is shown on the stress-strain curves formaterials undergoing a strength test.
Q: The representative curves of the applied stress versus the number of cycles for different metals are…
A: From the given graph it can be clearly seen that the fatigue strength of steel is greater than the…
Q: Calculate the maximum force that a 2.5mm thick and 50mm wide nickel strip, having a yield strength…
A:
Q: Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion…
A: It is that point on stress-strain curve, till which stress is linearly varying with strain. As per…
Q: The intensity of stress which causes unit strain is called O(A) Unit mass O(B) Modulus of rigidity…
A: Stress is defined as the ratio of force upon cross sectional area . Strain is defined as the ratio…
Q: S Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until…
A: a). Proportional Limit : The proportional limit is the point up to which the stress-strain curve is…
Q: An extruded polymer beam is sub]ected to a bending moment M. The length of the beam is L= 860 mm.…
A:
Q: Time l Which of the following is associated with minimum plastic deformation? O a. Ductile fracture…
A: Answer :- Option b Brittle fracture In a brittle fracture, the amount of plastic deformation in…
Q: Briefly explain the (a) how and (b) why the size of elastic deformation changes as the thickness of…
A:
Q: A copper rod with a diameter of 24 mm is subjected to tension within the elastic region. If the…
A: The given data is: Diameter of copper rod (d) = 24 mm Modulus of Elasticity (E) = 115 GPa Poisson's…
Q: 1: For a material stress at proportionality limit is 400 MPa and modulus of elasticity is 200 MPa.…
A:
Q: 5) A single zinc crystal is loaded in tension with the normal to its slip plane at 60° to the…
A: Given:Zinc crystal Tensile stress=0.69MPa Shear stress=0.94MPa
Q: A cylindrical aluminum alloy rod with a 0.5 in. diameter is subjected to ten- sion. Determine the…
A:
Q: Bulk Deformation Processes ,they are generally characterized by significant deformations and massive…
A: The given statement is False.
Q: Draw a tensile stress-strain curve for a typical semi-crystalline polymer such as LLDPE, and define…
A:
Q: The tensile strength vs. temperature curves of aluminum are plotted below. Explain the meaning of…
A: Given the plot of strength vs temperature for aluminium as, The meaning of the graphs have to be…
Q: effect of crosslinks on an elastomer
A: Elastomers are loosely cross-linked polymers. They have the characteristics of rubber in terms of…
Q: If a material has identical elastic properties in all directions, it is said to be (a) elastic (c)…
A: If a material has identical elastic properties in all direction it is said to be isotropic material…
Q: Determine the percentage of ductility of a metal alloy having the following tensile stress-strain…
A: From the given tensile stress-strain diagram of a metal alloy, The strain at limit of…
Q: An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 680 mm.…
A:
Q: When applying a shear force in a material that has an edge dislocation, what is the direction of the…
A: 18. Perpendicular Edge dislocation can be defined as a defect where some extra plane atoms are…
Q: A piece of metal has a Young's Modulus of 160,000 MPa, and a Poisson's ratio of 0.25. Calculate the…
A:
Q: An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 680 mm.…
A:
![3.What is a dislocation? List five more microscopic defects in bulk materials. Which of the
following properties are most sensitive to dislocation structures in materials?
a. Young's modulus
b. Yield strength
c. Conductivity
d. Transparency](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2054573b-afd7-43b3-bed5-d29827b76934%2F53e867cf-ebd8-4066-90b9-6502d4c7abf7%2Fccj45k_processed.jpeg&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
- Which of the following statements are true of dislocations? Select one or more: a. Dislocations can be viewed with high powered microscopy and not with the naked eye b. Dislocations can move under stress c. Dislocations can arise due to shear deformation of the lattice Od. Dislocations primarily enable high stiffness in metalsWhich of the following statements are true of dislocations? Select one or more: O a. Dislocations can move under stress O b. Dislocations can arise due to shear deformation of the lattice O C. Dislocations can be viewed with high powered microscopy and not with the naked eye Od. Dislocations primarily enable high stiffness in metalsPermanent deformations in structures refer to: A. linear elastic deformations B. deflection diagram C. linear inelastic deformation D. plastic deformation
- At a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 12.3 × 106/°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 8.9 x 10-6/°F] bar with a width of 2 in. and a thickness of 0.75 in. The supports at A and C are rigid. Determine the lowest temperature at which the two bars contact each other. (1) 3 in. 32 in. O 80.1°F O 118.6°F O 150.7°F O 132.9°F O 110.9°F B 2 in. 44 in. 0.04-in. gapAt a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 12.7 x 10-6/°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 8.6 x 10-6/°F] bar with a width of 2 in. and a thickness of 0.75 in. The supports at A and C are rigid. Determine the lowest temperature at which the two bars contact each other. (1) 3 in. 32 in. 90.2°F O 69.9°F 139.2°F 103.5°F O 111.0°F B ↑ 2 in. ↓ 44 in. -0.04-in. gapA copper rod is deformed using a uniaxial tensile force of 16000 N. Deformation continues until sufficient strain hardening has occurred such that the applied force is too small to allow further deformation. After deformation, the rod has a diameter of 0.01 m and a length of 1.5 m. Assume that copper follows the strain hardening lawwith K of 310 MPa and n=0.54 Please calculate the true strain after the deformation ?
- the cross-sectional area of the bar 1 of the two bars supported on the left and right sides is 1.2 cm^2, the coefficient of thermal expansion is 20.9 10^(-6)/K; The cross-sectional area of bar 2 is 3 cm^2 and its coefficient of thermal expansion is 25.4 10^(-6)/K. Since the modulus of elasticity of the material is 207 GPa, these two bars are heated to 99 °C.a) What will be the change in length (mm) of bar 1?b) What is the stress in bar 1 in MPa?c) What is the stress in bar 2 in MPa?At a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 14.4 x 10-6/°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 9.6 × 10-6/°F] bar with a width of 2 in. and a thickness of 0.75 in. The supports at A and Care rigid. Determine the lowest temperature at which the two bars contact each other. (1) 3 in. 32 in. 105.3°F 75.3°F O 147.3°F 86.6°F 113.4°F B ↑ 2 in. ↓ (2) 44 in. 0.04-in. gapAt a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 13.4 x 10-6/°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 10.1 x 10-6/°F] bar with a width of 2 in. and a thickness of 0.75 in. The supports at A and Care rigid. Determine the lowest temperature at which the two bars contact each other. (1) ↑ 3 in. 32 in. O 75.9°F O 146.5°F O 105.8°F O 122.3°F O 111.3°F 2 in. (2) 44 in. -0.04-in. gap
- At a temperature of 60°F, a 0.02-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; α=α=12.5 x 10-6/°F] bar with a width of 2.8 in. and a thickness of 0.85 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; α=α=9.6 x 10-6/°F] bar with a width of 1.6 in. and a thickness of 0.85 in. The supports at A and C are rigid. Assume h1=2.8 in., h2=1.6 in., L1=26 in., L2=40 in., and Δ=Δ= 0.02 in. Determine(a) the lowest temperature at which the two bars contact each other.(b) the normal stress in the two bars at a temperature of 225°F.(c) the normal strain in the two bars at 225°F.(d) the change in width of the aluminum bar at a temperature of 225°F.Strain = 600 Stress = Strain = 500 Stress = 400 500 300 400 300 200 200 100 100 0.000 0.002 0.004 0.006 Strain 0.00 0.04 0.08 0.12 0.16 0.20 Strain Stress (MPa)In an engineering application, the material is a strip of iron with a fixed crystallographic structure subject to a tensile load during operation. The part failed (yielded) during operation and needs to be replaced with a component with better properties. You are told that two other iron strips had failed at yield stresses of 110 and 120 MPa, with grain sizes of 30 microns and 25 microns respectively. The current strip has a grain size of 20 microns. The diameter of the rod is 1 mm and the load applied is 100 N. What is the yield stress of the new part C and would you recommend it for operation? Select one: Oa. 133.5 MPa, yes O b. OC. Od Oe. 120.5 MPa, no 129.5, yes 140.5, no 123.5 MPa, yes
![Materials Science And Engineering Properties](https://www.bartleby.com/isbn_cover_images/9781111988609/9781111988609_smallCoverImage.gif)
![Materials Science And Engineering Properties](https://www.bartleby.com/isbn_cover_images/9781111988609/9781111988609_smallCoverImage.gif)