3.IfOis glvenWo Li12 EI,Aas Eg=EIIEIzexpression TAfor Ve at the enelof.Find au--thethe overhomg beam Be using Tables inAppendix gd APPENDIXCANTILEVERED BEAM SLOPES AND DEFLECTIONS815SLOPES ANDCantilevered Beam Slopes and DeflectionsDEFLECTIONS OFBeamSlopeDeflectionElastic CurveBEAMS"max-PL-PL'Oman(3L - x)6EI2EI3EISimply Supported Beam Slopes and DeflectionsBeamSlopeDeflectionElastic Curve-P12EL 3L - 2x) 0sxS L/2P-Px(31 - 4x)48EI-5PL-PL.-PL.-PL?e =SEI16EI48EI48EI4RET (6x - L) L/2 sxSI,48EI-Pab(L + b)- Pbx6EIL L - -GEIL.-a 12 - -l' - - a')6EILPab(L + a)-wl.'(x2 - 41x + 62)24EI6EIL.SEJ-ML-M, L6EI"max =-Mox9V3 EI(L? - x)6EIL8, =3EIat x = 0.5774LMol-wL-5wL-WXr' - 2Lx + L')M VnasEl2EIBmasPmax24EI24EI384EI-WN(16r - 24Lx + 9L')-SwL384EI- 3wl768EI0, =0SxS L/224EI - 2Lx + L)128EI-wL(8x384EIwL2 =24LX7wL'Fman - -0.006563EI-7wl"28, =+ 17Lx - L')48EIEmas384EI384EIat x = 0.4598LL/2 sx

Answered: Image /qna-images/answer/3703e943-8818-4ff1-aa79-2984aee12168.jpg

Answered: 3.Ifisgluen Wo Li 12 EI, A as Eg= EII…

3.Ifisgluen Wo Li 12 EI, A as Eg= EII EIz Find au expression. A for Ve at the enlof. the the overhomg beam Be using Tables in Appendin d

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

3.IfOis glven
Wo Li
12 EI,
A
as Eg=
EII
EIz
expression TA
for Ve at the enelof.
Find au
--the
the overhomg beam Be using Tables in
Appendix gd

APPENDIX
CANTILEVERED BEAM SLOPES AND DEFLECTIONS
815
SLOPES AND
Cantilevered Beam Slopes and Deflections
DEFLECTIONS O
F
Beam
Slope
Deflection
Elastic Curve
BEAMS
"max
-PL
-PL'
Oman
(3L - x)
6EI
2EI
3EI
Simply Supported Beam Slopes and Deflections
Beam
Slope
Deflection
Elastic Curve
-P
12EL 3L - 2x) 0sxS L/2
P
-Px
(31 - 4x)
48EI
-5PL
-PL.
-PL.
-PL?
e =
SEI
16EI
48EI
48EI
4RET (6x - L) L/2 sxSI,
48EI
-Pab(L + b)
- Pbx
6EIL L - -
GEIL.
-a 12 - -
l' - - a')
6EIL
Pab(L + a)
-wl.'
(x2 - 41x + 62)
24EI
6EIL.
SEJ
-ML
-M, L
6EI
"max =
-Mox
9V3 EI
(L? - x)
6EIL
8, =
3EI
at x = 0.5774L
Mol
-wL
-5wL
-WX
r' - 2Lx + L')
M Vnas
El
2EI
Bmas
Pmax
24EI
24EI
384EI
-WN
(16r - 24Lx + 9L')
-SwL
384EI
- 3wl
768EI
0, =
0SxS L/2
24EI - 2Lx + L)
128EI
-wL
(8x
384EI
wL
2 =
24LX
7wL'
Fman - -0.006563
EI
-7wl"
2
8, =
+ 17Lx - L')
48EI
Emas
384EI
384EI
at x = 0.4598L
L/2 sx<I.
384EI (8t - LI
L/2 s xSL
-7w
"men = -0.00652
El
360EI
(3x - 10L' + 7L
360EIL
at x= 0.5193/.
6, =
45EI
-,L'
120EU (10L - 102x + 5Lx? - xP)
120EIL
814
24EI
30EI

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