3.90. There are four numbered balls in a box: 2 white and 2 black. In how many ways can 2 balls be chosen, among which at most one will be black? (a) List all the possibilities. b) Why the number of ways in point a ) cannot be calculated in the following way: we choose one white ball in 1 ways and another ball any of the remaining balls in ways, 1 so together we have 2· 3=6ways?
3.90. There are four numbered balls in a box: 2 white and 2 black. In how many ways can 2 balls be chosen, among which at most one will be black? (a) List all the possibilities. b) Why the number of ways in point a ) cannot be calculated in the following way: we choose one white ball in 1 ways and another ball any of the remaining balls in ways, 1 so together we have 2· 3=6ways?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps
Recommended textbooks for you
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON