3.35 A horizontal curve on a two-lane highway (10-ft lanes) is designed for 50 mi/h with a 6% superelevation. The central angle of the curve is 35 degrees and the PI is at station 482 +72. What is the station of the PT and how many feet have to be cleared from the lane's shoulder edge to provide adequate stopping sight distance?

A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the last deflection angle (degrees)  (i.e. the angle subtended by the roadway between the last full station and the PT)?

A section of a two-lane highway (one lane in each direction) (12-ft lanes) is designed for 55 mi/h. At one point a vertical curve connects a -2.9% and +1.8% grade. The PVT of this curve is at station 38 + 50. It is known that a horizontal curve starts (has PC) 247 ft before the vertical curve's PVC. If the superelevation of the horizontal curve is 0.08 and the central angle is 39 degrees, what is the station of the PT (express station in the format 0.00, for example, station 10+50 must be expressed as 10.5)?

A circular curve of the highway is designed for traffic moving at 50 mi/hr. If the radius of the curve is 550 ft, what is the correct angle of banking of the road?