3. Which compound is likely to have a higher boiling point? Why a. A polar compound without O-H or N-H bonds, or a polar compound with O-H or N-H bonds b. CH3CH2CH2OH or CH3(CH2)4OH
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3. Which compound is likely to have a higher boiling point? Why
a. A polar compound without O-H or N-H bonds, or a polar compound with O-H or N-H bonds
b. CH3CH2CH2OH or CH3(CH2)4OH
4. Compare boiling points and solubilities in water for each pair of compounds. Explain
a. Ammonia, NH3 and methane, CH4
b. Pentanol, C5H11OH, and pentane, C5H12
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- 4. Which compound do you expect to be more soluble in octane (C8H18)? a. CH3OH b. H₂O C. CC14 d. NH3 Explain the reason for your choice:Chemistry 1. Glycerol, CH2(OH)CH(OH)CH2OH, has a 3 carbon chain with -OH groups coming off of each carbon. This thick, syrup like liquid is used in anti-freeze and as a food additive. Hexaoctane, C18H38, is a greasy wax-like solid at room temperature. Using this information rank molecules in order of increasing boiling point and justify your answer: PCl2F, H2O, SeS3, MgS, Glycerol, CH4, CaS, PF2Cl, Hexaoctane, NeConsider the data in the table. Compound Melting point (°C) ????? (??/???)ΔHfus (kJ/mol) Boiling point (°C) ????? (??/???)ΔHvap (kJ/mol) HFHF −83.11 4.577 19.54 25.18 HClHCl −114.3 1.991 −84.9 17.53 HBrHBr −86.96 2.406 −67.0 19.27 HIHI −50.91 2.871 −35.38 21.16 Using the data in the table, calculate Δ?fus and Δ?vap for HF. Δ?fus= J/(K⋅mol) Δ?vap= J/(K⋅mol) Determine the entropy change when 8.70 mol HF(g) condenses at atmospheric pressure. Δ?= J/K
- Consider the data in the table. Compound Melting point (°C) ????? (??/???)ΔHfus (kJ/mol) Boiling point (°C) ????? (??/???)ΔHvap (kJ/mol) HFHF −83.11 4.577 19.54 25.18 HClHCl −114.3 1.991 −84.9 17.53 HBrHBr −86.96 2.406 −67.0 19.27 HIHI −50.91 2.871 −35.38 21.16 Using the data in the table, calculate Δ?fusΔSfus and Δ?vapΔSvap for HF.HF. Δ?fus=ΔSfus= J/(K⋅mol)J/(K⋅mol) Δ?vap=ΔSvap= J/(K⋅mol)J/(K⋅mol) Determine the entropy change when 7.60 mol HF(l)7.60 mol HF(l) boils at atmospheric pressure. Δ?=ΔS= J/K1. Which of the following compounds would have the greatest degree of solubility in water? Explain why. OH OH t OH9. Draw Lewis Structures of the following compounds: (You will use these Lewis Structures to predict intermolecular forces.) 1. Compound V (CH3CH3) 2. Compound W (HOCH2CH2OH) 3. Compound X (CH3CH2CH3) 4. Compound Y (CH3CH2OH). 5. Compound Z (CH3-O-CH3)
- 3. The following 4 compounds; CH₁, CH₂Cl, and CH,OH, are very similar in structure, but have very different boiling points. Explain why. IWhich statement is incorrect concerning these two molecules with the same formula, C,H,O? H. 1. H. H C -C H C - -C H. H. H. 1. II. a. compound (II) will more likely be soluble in water than compound (1) b. compound (I) will have a lower boiling point than compound (II) c. hydrogen bonding will be the most like ly for compound (II) d. the vapour pressure of compound (II) will be lower than that of compound (I) at a given temperature e. compound (I) would be a better solvent12. Normal boiling point of ethanol (C2H5OH) is 78 °C, and of propanol (C3H;OH) is 97 °C. a. Explain the reason for the difference in boiling points of these two alcohols. b. When the underline methyl group in propanol, CH3CH2CH2OH, is replaced with a hydroxyl group (HOCH2CH2OH), boiling point of the molecule increases to 197 °C. Explain the reason for observed increase in the boiling point.
- Which is more soluble in octane, C8H18: propane CH3-CH2-CH3 OR 1-propanol, CH3-CH2-CH2-OH. Why? a. propane, only has dispersion forces. b. 1-propanol, because it can hydrogen bond. c. 1-propanol, because it has strong dispersion forces.Why does CH3OH have a higher boiling point than CCl4? Explain in terms of intermolecular forces. Select the single best answer. Because CH3OH is soluble in water, and CCl4 is not. Because CH3OH can form hydrogen bonds, and CCl4 can't. Because CH3OH is a liquid, and CCl4 is a gas. Because CH3OH is an ionic compound, and the ion-ion attractions are much stronger than the dispersion forces between CCl4 molecules.Essential oils are concentrated liquid containing metabolites extracted from plant sources and are widely used in the production of perfumes. The structures of some of these compounds present in essential oils, along with acetone, are presented below. CH3 H2C CH H2 H3CO, CH2 CH H2C H2C CH FCH2 HO H3C CH2 Compound A MM: 164.2 g/mol Boiling Point: 254 C Compound B MM: 162.19 g/mol Boiling Point: 232 C Compound C MM: 136.24 g/mol Boiling Point: 176 C Determine the most possible boiling point of each of the compounds. Refer to the possible boiling points listed above. An equal volume of COMPOUNDS A, B and C were stored in separate beakers which were left uncovered at room temperature. 1. 2. If the three liquids were allowed to stand for about 10 minutes, which of the following will have the least amount of liquid b. What physical property is the basis of the answer? Among the three liquids, what is the most recommended ingredient of a perfume that will have the most lasting scent? а.…