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3. Using the truncated viral equation of state given below, nRT n°RTB(T) P =- V?

3. Using the truncated viral equation of state given below, nRT n°RTB(T) P =- V?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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solve part C

3. Using the truncated viral equation of state given below, nRT n° RTB(T) P = V .(a) Calculate the amount of work done as 500 mol of acetone (g) is compressed isothermally from 500 to 2.00 dm at 363 K with B(T) = B(363 K) =-874 cm³ mol-'. (b) Next, calculate the same isothermal compression, however, in this case for 500 mol of neon (g) at 363 K whose second Virial coefficient is B(T) = B(363 K) = 12.1 cm³ mol-. (c) Finally, compare and contrast these two values of compressive work (wompresion). Speculate on why acetones result comes out the way that it does; i.e., what molecular or chemical rationale can explain its result.
Transcribed Image Text:3. Using the truncated viral equation of state given below, nRT n° RTB(T) P = V .(a) Calculate the amount of work done as 500 mol of acetone (g) is compressed isothermally from 500 to 2.00 dm at 363 K with B(T) = B(363 K) =-874 cm³ mol-'. (b) Next, calculate the same isothermal compression, however, in this case for 500 mol of neon (g) at 363 K whose second Virial coefficient is B(T) = B(363 K) = 12.1 cm³ mol-. (c) Finally, compare and contrast these two values of compressive work (wompresion). Speculate on why acetones result comes out the way that it does; i.e., what molecular or chemical rationale can explain its result.
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