3. The linear operator T: R³ R³ is defined by T(x1, x2, x3) = (W1₁, W2, W3), where w₁ = 2x₁ + 4x2 + x3; W2 = 9x2 + 2x3; W3 = 2x1 - 8x2 - 2x3. Which of the following is correct. (a) T is not one to one. (b) T is one to one but the standard matrix for T-1 does not exist. 0 (c) T is one to one and its standard matrix for T-¹ is 1 -4 -3 3 3 (d) T is one to one and its standard matrix for T-1 is 0 1 -4 -3 1 2 6 3 (e) None of these 13 23 3 2/31 2²/12 3 162/3 3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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### Linear Operator: Evaluation and Properties

Consider the linear operator \( T: \mathbb{R}^3 \rightarrow \mathbb{R}^3 \) defined by \( T(x_1, x_2, x_3) = (w_1, w_2, w_3) \), where:
\[ w_1 = 2x_1 + 4x_2 + x_3 \]
\[ w_2 = 9x_2 + 2x_3 \]
\[ w_3 = 2x_1 - 8x_2 - 2x_3 \]

**Question:** Which of the following statements is correct?

(a) \( T \) is not one to one.  
(b) \( T \) is one to one.  
(c) \( T \) is one to one but the standard matrix for \( T^{-1} \) does not exist.  
(d) \( T \) is one to one and its standard matrix for \( T^{-1} \) is   
\[ \begin{pmatrix}
\frac{1}{6} & 0 & \frac{1}{6} \\
0 & \frac{1}{3} & \frac{1}{3} \\
\frac{1}{12} & -\frac{1}{4} & -\frac{7}{12}
\end{pmatrix} \]  
(e) None of these.

### Analysis of Options

#### Option (a)
- **Statement:** \( T \) is not one to one.
- **Analysis:** To verify this, we need to check the kernel of \( T \). If the kernel contains only the zero vector, \( T \) is one to one. Otherwise, it is not.

#### Option (b)
- **Statement:** \( T \) is one to one.
- **Analysis:** This implies that the transformation is injective. We can verify this by determining if the determinant of the transformation matrix is non-zero.

#### Option (c)
- **Statement:** \( T \) is one to one but the standard matrix for \( T^{-1} \) does not exist.
- **Analysis:** If \( T \) is one to one, the inverse exists. For the inverse matrix to exist and be valid, the standard matrix of \( T \) should be invertible.

#### Option (d)
Transcribed Image Text:### Linear Operator: Evaluation and Properties Consider the linear operator \( T: \mathbb{R}^3 \rightarrow \mathbb{R}^3 \) defined by \( T(x_1, x_2, x_3) = (w_1, w_2, w_3) \), where: \[ w_1 = 2x_1 + 4x_2 + x_3 \] \[ w_2 = 9x_2 + 2x_3 \] \[ w_3 = 2x_1 - 8x_2 - 2x_3 \] **Question:** Which of the following statements is correct? (a) \( T \) is not one to one. (b) \( T \) is one to one. (c) \( T \) is one to one but the standard matrix for \( T^{-1} \) does not exist. (d) \( T \) is one to one and its standard matrix for \( T^{-1} \) is \[ \begin{pmatrix} \frac{1}{6} & 0 & \frac{1}{6} \\ 0 & \frac{1}{3} & \frac{1}{3} \\ \frac{1}{12} & -\frac{1}{4} & -\frac{7}{12} \end{pmatrix} \] (e) None of these. ### Analysis of Options #### Option (a) - **Statement:** \( T \) is not one to one. - **Analysis:** To verify this, we need to check the kernel of \( T \). If the kernel contains only the zero vector, \( T \) is one to one. Otherwise, it is not. #### Option (b) - **Statement:** \( T \) is one to one. - **Analysis:** This implies that the transformation is injective. We can verify this by determining if the determinant of the transformation matrix is non-zero. #### Option (c) - **Statement:** \( T \) is one to one but the standard matrix for \( T^{-1} \) does not exist. - **Analysis:** If \( T \) is one to one, the inverse exists. For the inverse matrix to exist and be valid, the standard matrix of \( T \) should be invertible. #### Option (d)
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