3. The irreversible first order liquid phase reaction A →R is to be carried out in an insulated mixed flow reactor. The feed enters in to the reactor at 25°C. The concentration of the reactant (A) is 1 kmol/m3 and the volumetric flow rate is 0.025 m/sec in the feed. The reactor is equipped with cooling system to keep the reactor temperature constant and coolant fluid enters to the cooling coil, placed in to the reactor, at 15°C and leaves at 20°C. Calculate the heat transfer area required. Data: AH= -1.46x107 J/mol k298 = 0.11 sn! V= 6 m3 %3D Uo= 2280 J/(m².sec.K) (Overall heat transfer coefficient)
3. The irreversible first order liquid phase reaction A →R is to be carried out in an insulated mixed flow reactor. The feed enters in to the reactor at 25°C. The concentration of the reactant (A) is 1 kmol/m3 and the volumetric flow rate is 0.025 m/sec in the feed. The reactor is equipped with cooling system to keep the reactor temperature constant and coolant fluid enters to the cooling coil, placed in to the reactor, at 15°C and leaves at 20°C. Calculate the heat transfer area required. Data: AH= -1.46x107 J/mol k298 = 0.11 sn! V= 6 m3 %3D Uo= 2280 J/(m².sec.K) (Overall heat transfer coefficient)
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:3. The irreversible first order liquid phase reaction
A →R
is to be carried out in an insulated mixed flow reactor. The feed enters in to the reactor at
25°C. The concentration of the reactant (A) is 1 kmol/m3 and the volumetric flow rate is
0.025 m3/sec in the feed. The reactor is equipped with cooling system to keep the reactor
temperature constant and coolant fluid enters to the cooling coil, placed in to the reactor, at
15°C and leaves at 20°C. Calculate the heat transfer area required.
k298 = 0.11 sn
Uo= 2280 J/(m².sec.K) (Overall heat transfer coefficient)
Data: AH2= -1.46x107 J/mol
V= 6 m3
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