3. The ground state and first excited state of the SHO for angular frequency w are Yo (x) = a exp[-½/2²] ¥₁ (x) = a 2¹/2² ₹ exp [ - ½ ₹² ] where α = (mw/Ãħ)¹/4 and ₹ = (mw/ħ)¹/² x. (a) Construct the second excited state 2 (x) by applying the raising operator. (b) Sketch yo (x), 4₁ (x), and 42 (X). (c) Check their orthogonality. (d) Compute directly and < V> for yo (x) and verify the answers agree with the known total energy E. [T means kinetic energy here].

icon
Related questions
Question
3. The ground state and first excited state of the SHO for angular frequency o are
Yo (x) = a exp[-½ ²]
4₁ (x) = a 2¹/² exp[-½ ²]
where α = (mo/πħ)¹/4 and } = (mw/ħ)¹/² x.
(a) Construct the second excited state 2 (x) by applying the raising operator.
(b) Sketch 40 (x), 4₁ (x), and 42 (X).
(c) Check their orthogonality.
(d) Compute directly <T> and < V > for Yo (x) and verify the answers agree with the known total
energy E. [T means kinetic energy here].
Transcribed Image Text:3. The ground state and first excited state of the SHO for angular frequency o are Yo (x) = a exp[-½ ²] 4₁ (x) = a 2¹/² exp[-½ ²] where α = (mo/πħ)¹/4 and } = (mw/ħ)¹/² x. (a) Construct the second excited state 2 (x) by applying the raising operator. (b) Sketch 40 (x), 4₁ (x), and 42 (X). (c) Check their orthogonality. (d) Compute directly <T> and < V > for Yo (x) and verify the answers agree with the known total energy E. [T means kinetic energy here].
Expert Solution
steps

Step by step

Solved in 6 steps with 13 images

Blurred answer