College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Can u please answer 3,4, and 5 please?
Velocity, and Acceleration HW 1. On three different planets, the following functions express the height of an object that is thrown downward and is falling 200 metres. Neptune: h(t)=-5.88t² – 8t+ 200 h'(t):-|1.764 -8 h"(1):-1l.16 Mars: h(t)=-1.85t² – 8t +200 h' (F) - -3.7t -8 h'(1):-3. Venus: h(t)=-4.45t² –8t +200 h'():-8.94-8 h"(+):-89 a) What is the acceleration due to gravity on each planet? heptune:-1 16 mis mars: -3.1 mis venus:-8,9m/s? 2. The displacement S (In meters) of a particle is related with time t(in seconds) as S = 3t3 + 4t2 + 3t + 2 The velocity of the particle when t = 3 sec is V: 91?.843 a. O 105 m/sec b. O 27 m/sec c. O 108 m/sec d. O 42 m/s 3. The displacement S in metres traversed by a particle with time t in seconds is given by S = 6t2 + 7t + 4. Find the average velocity of the particle between t = 0 andt = 4. a. O 128 m/s b. O - 31 m/s c. O 31 m/s d. O 124 m/s The height S feet reached in time t seconds by a stone projected vertically upwards is given by S = 128t - 16t2. wWhat is the maximum height reached by the stone? 4. a. O 4 ft b. O 256 ft c. O 512 ft d. O 32 ft 5. The position equation of the movement of a particle is given by s = (t² –1 where s is measured in feet and t is measured in seconds. Find the acceleration at 2 seconds.
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Transcribed Image Text:Velocity, and Acceleration HW 1. On three different planets, the following functions express the height of an object that is thrown downward and is falling 200 metres. Neptune: h(t)=-5.88t² – 8t+ 200 h'(t):-|1.764 -8 h"(1):-1l.16 Mars: h(t)=-1.85t² – 8t +200 h' (F) - -3.7t -8 h'(1):-3. Venus: h(t)=-4.45t² –8t +200 h'():-8.94-8 h"(+):-89 a) What is the acceleration due to gravity on each planet? heptune:-1 16 mis mars: -3.1 mis venus:-8,9m/s? 2. The displacement S (In meters) of a particle is related with time t(in seconds) as S = 3t3 + 4t2 + 3t + 2 The velocity of the particle when t = 3 sec is V: 91?.843 a. O 105 m/sec b. O 27 m/sec c. O 108 m/sec d. O 42 m/s 3. The displacement S in metres traversed by a particle with time t in seconds is given by S = 6t2 + 7t + 4. Find the average velocity of the particle between t = 0 andt = 4. a. O 128 m/s b. O - 31 m/s c. O 31 m/s d. O 124 m/s The height S feet reached in time t seconds by a stone projected vertically upwards is given by S = 128t - 16t2. wWhat is the maximum height reached by the stone? 4. a. O 4 ft b. O 256 ft c. O 512 ft d. O 32 ft 5. The position equation of the movement of a particle is given by s = (t² –1 where s is measured in feet and t is measured in seconds. Find the acceleration at 2 seconds.
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