3. Let - (10-¹6 1) A = b-(3) and b = Here we will see the effect of using a tiny element as a pivot. (a) By hand, solve the linear system Ax - b exactly. Write your answer in a form where it is clear what the approximate values of x₁ and x₂ are. (b) In MATLAB, enter the matrix A and type cond (A) to determine the 2-norm condition number of A. Would you say that this matrix is well conditioned or ill conditioned in the 2-norm? = (c) Write a MATLAB code (or use one from the text) that does not do partial pivoting to solve the linear system Ax b. Compare the answer returned by this code to the one that you determined by hand

I need help with my MATLAB code. I am using ode45 to solve my differential equation. But, the size of w_ode is 9x645. Size of t is also 1x645. How is that possible? Shouldn't t be 1x101 and w_ode be 9x101? How do I get the size to be 9x101? I need that size because I am subtract that matrix by another matrix of the same size. I_T = 2;J = 1.5;I = [I_T; I_T; J];w = [-0.1; 0.3; -1.1];L = [0;0;0]; t = 0:100; % Using ode45 to integrate w dotoptions = odeset('RelTol',1e-10,'AbsTol',1e-10);result = ode45(@dwdt_Bframe, t, [w; I; L], options); % Extracting information from ode solvert = result.xw_ode = result.y     function dwdt = dwdt_Bframe(t, wIL)     w = wIL(1:3);    I = wIL(4:6);    L = wIL(7:9);     % The w dot equations    dwdt = zeros(9,1);    dwdt(1) = (-(I(3) - I(2))*w(2)*w(3) + L(1)) / I(1);    dwdt(2) = (-(I(1) - I(3))*w(3)*w(1) + L(2)) / I(2);    dwdt(3) = (-(I(2) - I(1))*w(1)*w(2) + L(3)) / I(3);         % Keep the values of I and L constant    dwdt(4:6) = 0;    dwdt(7:9) = 0; end

any idea how to solve ?

Answer the question using Python programming language and Numpy: