3. For the circuit below, find the Q-point for all diodes. You can do ONE of the three options (indicate model. Opuon B Option C se CVD diode model (Von = 0.5V). like B, but replace diode D2 with two identical diodes in series. 12 D V D, 1V 2V 5V

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### Circuit Analysis Problem

**Problem Statement:**

For the circuit below, find the Q-point for all diodes. You can do ONE of the three options (indicate which):

1. Use ideal diode model.
2. Use CVD diode model \( (V_{on} = 0.5V) \).
3. Like B, but replace diode \( D_2 \) with two identical diodes in series.

**Circuit Diagram:**
\[
\begin{array}{c}
\begin{array}{c}
\begin{array}{ccc}
 & \; 1\Omega & \; \; \; \; \; \; \; 2\Omega  \\
 | & \; \;  & \; \; \; \; \; \; \; \;  \\
 | & \; \;  & \; \; \; \; \; \; \; \;  \\
1V \; & \; \; D_1  & \; \; \; \; \; \; D_2 \\
 | & \; \;  & \; \; \; \; \; \; \; | \; \; 2V \; \; 5V
 \end{array}
 \end{array} 
 \end{array}
\]

**Explanation of the Circuit Diagram:**

The circuit consists of two branches with diodes \(D_1\) and \(D_2\). Here's a detailed explanation:

- The left branch includes:
  - A \( 1\Omega \) resistor in series with diode \( D_1 \).
  - A voltage source of \( 1V \) is applied across the branch.

- The right branch includes:
  - A \( 2\Omega \) resistor in series with diode \( D_2 \).
  - A voltage source of \( 2V \) is applied across the resistor and diode series combination.
  - An additional voltage source of \( 5V \) is applied across the entire branch including both the \( 2\Omega \) resistor and \( D_2 \).

You need to choose one modeling option (either ideal, CVD, or the modified CVD with two diodes in series) to analyze the circuit and find the Q-point (operating point) for each diode.
Transcribed Image Text:### Circuit Analysis Problem **Problem Statement:** For the circuit below, find the Q-point for all diodes. You can do ONE of the three options (indicate which): 1. Use ideal diode model. 2. Use CVD diode model \( (V_{on} = 0.5V) \). 3. Like B, but replace diode \( D_2 \) with two identical diodes in series. **Circuit Diagram:** \[ \begin{array}{c} \begin{array}{c} \begin{array}{ccc} & \; 1\Omega & \; \; \; \; \; \; \; 2\Omega \\ | & \; \; & \; \; \; \; \; \; \; \; \\ | & \; \; & \; \; \; \; \; \; \; \; \\ 1V \; & \; \; D_1 & \; \; \; \; \; \; D_2 \\ | & \; \; & \; \; \; \; \; \; \; | \; \; 2V \; \; 5V \end{array} \end{array} \end{array} \] **Explanation of the Circuit Diagram:** The circuit consists of two branches with diodes \(D_1\) and \(D_2\). Here's a detailed explanation: - The left branch includes: - A \( 1\Omega \) resistor in series with diode \( D_1 \). - A voltage source of \( 1V \) is applied across the branch. - The right branch includes: - A \( 2\Omega \) resistor in series with diode \( D_2 \). - A voltage source of \( 2V \) is applied across the resistor and diode series combination. - An additional voltage source of \( 5V \) is applied across the entire branch including both the \( 2\Omega \) resistor and \( D_2 \). You need to choose one modeling option (either ideal, CVD, or the modified CVD with two diodes in series) to analyze the circuit and find the Q-point (operating point) for each diode.
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