3. FBD for AK to determine the internal forces on K: forces/reactions on the AK; a. There are b. Sum axial forces to zero, solve that nominal force FK = c. Sum tangential forces to zero, solve that shear force VK d. Sum moment about point = N; direction is pointing to the N; direction is pointing to the solve that bending moment on k is MK = Nm; direction is pointing to the

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter2: Basic Operations With Force Systems
Section: Chapter Questions
Problem 2.80P: The figure shows one-half of a universal coupling known as the Hooke's joint. The coupling is acted...
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This is homework question #3 Pls help
Knowing that the radius of each pulley is 200 mm and neglecting friction, external force is
360 N. Determine the internal forces at Points J and K of the frame shown.
Solution:
1. FBD for frame and pulleys together:
a. There are
supports on the frame, they are both
reactions on the supports, for a 2D body, this is statically
are
b. Sum moment about point
c. Sum all the horizonal forces to zero, solve that Ax
2. FBD for Member AE:
d. Sum all the vertical forces to zero, yield that Ay + By
=
a. There are
b. Sum moment about point
solve that B =
c. Thus By
=
N; direction is pointing to the
a. There are
=
→
N; direction is pointing to the
forces/reactions on the member AE, for a 2D body, this is statically
d. Sum all the horizontal forces to zero, solve that Ex
=
3. FBD for AK to determine the internal forces on K:
forces/reactions on the AK;
and note that the tension force in the cable on D is
all together there
N; direction is pointing to the
→
N;
→
N; direction is pointing to the
1.8 m
N; direction is pointing to the
in pointing to the
B
0.8 m
◆
D
→
K
0.8 m
solve that Ay =
0.8 m
Transcribed Image Text:Knowing that the radius of each pulley is 200 mm and neglecting friction, external force is 360 N. Determine the internal forces at Points J and K of the frame shown. Solution: 1. FBD for frame and pulleys together: a. There are supports on the frame, they are both reactions on the supports, for a 2D body, this is statically are b. Sum moment about point c. Sum all the horizonal forces to zero, solve that Ax 2. FBD for Member AE: d. Sum all the vertical forces to zero, yield that Ay + By = a. There are b. Sum moment about point solve that B = c. Thus By = N; direction is pointing to the a. There are = → N; direction is pointing to the forces/reactions on the member AE, for a 2D body, this is statically d. Sum all the horizontal forces to zero, solve that Ex = 3. FBD for AK to determine the internal forces on K: forces/reactions on the AK; and note that the tension force in the cable on D is all together there N; direction is pointing to the → N; → N; direction is pointing to the 1.8 m N; direction is pointing to the in pointing to the B 0.8 m ◆ D → K 0.8 m solve that Ay = 0.8 m
3. FBD for AK to determine the internal forces on K:
forces/reactions on the AK;
a. There are
b. Sum axial forces to zero, solve that nominal force FK =
c. Sum tangential forces to zero, solve that shear force VK
=
d. Sum moment about point
4. FBD for BJ to determine the internal forces on J:
forces/reactions on the AK;
a. There are
b. Sum axial forces to zero, solve that nominal force FK =
c. Sum tangential forces to zero, solve that shear force VK =
d. Sum moment about point
solve that bending moment on k is MK
◆
N; direction is pointing to the
N; direction is pointing to the
N; direction is pointing to the
N; direction is pointing to the
solve that bending moment on J is MJ =
♦
Nm; direction is pointing to the
→
Nm; direction is pointing to the
Transcribed Image Text:3. FBD for AK to determine the internal forces on K: forces/reactions on the AK; a. There are b. Sum axial forces to zero, solve that nominal force FK = c. Sum tangential forces to zero, solve that shear force VK = d. Sum moment about point 4. FBD for BJ to determine the internal forces on J: forces/reactions on the AK; a. There are b. Sum axial forces to zero, solve that nominal force FK = c. Sum tangential forces to zero, solve that shear force VK = d. Sum moment about point solve that bending moment on k is MK ◆ N; direction is pointing to the N; direction is pointing to the N; direction is pointing to the N; direction is pointing to the solve that bending moment on J is MJ = ♦ Nm; direction is pointing to the → Nm; direction is pointing to the
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