3.F= 160,000 lbs.GRAY CAST IRON1.251.000.25501.00F =QUEA=F = 160,000 lbs.7.25J=Will it fail?

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Answered: 3. F= 160,000 lbs. GRAY CAST IRON 1.25…

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3. F= 160,000 lbs. GRAY CAST IRON 1.25 1.00 0.25 50 1.00 F = F= 160,000 lbs. 7.25 ult A= 1000 6= Will it fail?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conduction and Convection

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Question

3.
F= 160,000 lbs.
GRAY CAST IRON
1.25
1.00
0.25
50
1.00
F =
QUE
A=
F = 160,000 lbs.
7.25
J=
Will it fail?

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A) A circular rod with a gage length of 3.6 m and a diameter of 2.3 cm is subjected to an axial load of 51 kN . If the modulus of elasticity is 200 GPa , what is the change in length? B)A circular rod with a length of 4 m and a diameter of 2.4 cm is subjected to an axial load of 61 kN . If the resulting change in length is 3.34 mm , what is the modulus of elasticity? C)A circular rod with a length of 3.7 m and a diameter of 2.7 cm is subjected to an axial load and increases in length by 3.26 mm . The initial portion of the stress-strain curve of the material is given. What is the applied load?
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