3. By Similar Triangles Distance AC=4.2m Distance BC=8.88m a b. Distance Cb=? Distance Ca=2.29m OBS A Distance AB=? Given: A line through AB an obstruction. Required: To find the distance AB by similar triangle. Procedure: 1. Select a convenient point C, and measure AC and BC. 2. Set point a conveniently along AC and measure Ca. 3. Solve for Cb from: Cb : aC = BC : AC 4. Locate point b along BC by laying the computed distance Cb from C. 5. Measure ab. Solve for AB from: AB : AC = ab : Ca

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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3. By Similar Triangles
C
Distance AC=4.2m
Distance BC=8.88m
Distance Cb=?
Distance Ca=2.29m
OBS
A
Distance AB=?
Given: A line through AB an obstruction.
Required: To find the distance AB by similar triangle.
Procedure:
1. Select a convenient point C, and measure AC and BC.
2. Set point a conveniently along AC and measure Ca.
3. Solve for Cb from:
Cb : aC = BC : AC
4. Locate point b along BC by laying the computed distance Cb from C.
5. Measure ab. Solve for AB from:
AB : AC = ab : Ca
Transcribed Image Text:3. By Similar Triangles C Distance AC=4.2m Distance BC=8.88m Distance Cb=? Distance Ca=2.29m OBS A Distance AB=? Given: A line through AB an obstruction. Required: To find the distance AB by similar triangle. Procedure: 1. Select a convenient point C, and measure AC and BC. 2. Set point a conveniently along AC and measure Ca. 3. Solve for Cb from: Cb : aC = BC : AC 4. Locate point b along BC by laying the computed distance Cb from C. 5. Measure ab. Solve for AB from: AB : AC = ab : Ca
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