Q 3 please A. x² = y² +13.A.4. (5.A. y cie + c₂e63) The solution of = 5, y(1) = 1 is.B. y2x2+1A.8.A. y = ₁x + ₂x²us) The general solution of y" + 5y' -6y = 0 is.B. y cie-6 + c₂e9. (The integrating factor of xy' + 2y = is.C. ³B. 2A. e-t-) The general solution of r2y" - 3xy' + 4y = 0 is.B. y cr² + c₂r²ln(r)The radius of convergence of 1(-1)*3kk(x-4).B. 0C. 0011. (A. 3tet + etD. 36. (s) The minimum radius of convergence of power series solution about r= -2 of the ODE(x²-49)y" + 2xy' + y = 0..A. 7B. 8s) The value of {} is.B. et8443) The value of L-1{} is.B. 2tet + etA. 1A. e²(+²)-C. y² = 2x² +1The value of L{u(t-2)} is.B. e²(++)10. (The equivalent form ofUsing unit step functions isA. u(t-3) (tan(t) + 4) + 4D. 4u(t-3)-tan(t)u(t-3)C. ycie + c₂e-bxf(t) =C. y=+(2)C. 6The value of f tan(t)o(t-)dtB. 0C. u(t)C. 2te-t + etD. ²-x²=0.03B. u(t-3)(tan(t)-4) +4 C. 4u(t-3) + tan(t)u(t-3)D. 3te +etD. √2

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Answered: 3. A. us) The general solution of y" +…

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3. A. us) The general solution of y" + 5y' - 6y=0 is. B. y cie-6 + c₂e A. y cie + c₂e6 C. y = ce+c₂e-ba D. y=ce + ce

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter4: Polynomial And Rational Functions

Section4.3: Zeros Of Polynomials

Problem 68E

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Question

Q 3 please

A. x² = y² +1
3.
A.
4. (
5.
A. y cie + c₂e6
3) The solution of = 5, y(1) = 1 is.
B. y2x2+1
A.
8.
A. y = ₁x + ₂x²
us) The general solution of y" + 5y' -6y = 0 is.
B. y cie-6 + c₂e
9. (
The integrating factor of xy' + 2y = is.
C. ³
B. 2
A. e-t
-) The general solution of r2y" - 3xy' + 4y = 0 is.
B. y cr² + c₂r²ln(r)
The radius of convergence of 1(-1)*3kk(x-4).
B. 0
C. 00
11. (
A. 3tet + et
D. 3
6. (s) The minimum radius of convergence of power series solution about r= -2 of the ODE
(x²-49)y" + 2xy' + y = 0..
A. 7
B. 8
s) The value of {} is.
B. et
844
3) The value of L-1{} is.
B. 2tet + et
A. 1
A. e²(+²)
-
C. y² = 2x² +1
The value of L{u(t-2)} is.
B. e²(++)
10. (The equivalent form of
Using unit step functions is
A. u(t-3) (tan(t) + 4) + 4
D. 4u(t-3)-tan(t)u(t-3)
C. ycie + c₂e-bx
f(t) =
C. y=+(2)
C. 6
The value of f tan(t)o(t-)dt
B. 0
C. u(t)
C. 2te-t + et
D. ²-x²=0.
0<t<3
D.
D. y cez + cela
C. ₂
D. y = 2+2
D. 5
C. e(++) D. e² (3+²)
D. 8(t)
- {ian (1)
tan(t) t>3
B. u(t-3)(tan(t)-4) +4 C. 4u(t-3) + tan(t)u(t-3)
D. 3te +et
D. √2

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