3. A student titrated 20.00 mL of a weak base solution, 0.150 M CH3NH2 (Kb = 4.40 × 10-4) with 0.100 M HCl solution. Calculate the pH at the equivalence point.

Chemistry: Principles and Reactions
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Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 52QAP: A solution is prepared by dissolving 0.350 g of benzoic acid, HC7H5O2, in water to make 100.0 mL of...
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3. A student titrated 20.00 mL of a weak base solution, 0.150 M CH3NH2 (Kb = 4.40 × 10-4)
with 0.100 M HCl solution. Calculate the pH at the equivalence point.
Transcribed Image Text:3. A student titrated 20.00 mL of a weak base solution, 0.150 M CH3NH2 (Kb = 4.40 × 10-4) with 0.100 M HCl solution. Calculate the pH at the equivalence point.
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