3. A PVT cell containing pure water (H₂O) shows two equilibrium phases of vapor and liquid at 336.75°C. Answer the questions below by using Appendix A.III of Sandler, "steam table." What is the pressure (MPa) of the PVT cell? The visual window of the PVT cell shows 70 cm³ of vapor and 3 cm³ of liquid at What is the mass of water (a total of liquid water and vapor water) in the PVT cell? Since the water in the PVT cell shows two equilibrium phases at the temperature (and the corresponding pressure you answered in part a), it has no thermodynamic freedom (F = 0). When an additional heat is given to the system while keeping the temperature at 336.75°C and the pressure (that you answered in part a), the volume increases from 73 cm³ to 80 cm³. Note that the system is closed; hence, the total mass of water remains the same as Part b. What is the mass of liquid water, and what is the mass of vapor water? a. b. C. 336.75°C. a. 14 MPa 6₁ v ² = 1.611 cm ³ /g ML 3 cm³ = 1.8629 1.611 cm³/g Mwater = 1.862 g + 6,095g = 7.957g V = 11.485cm ³ /g = 3 my = 70cm³ 11.485 cm³/g = 6.0959
3. A PVT cell containing pure water (H₂O) shows two equilibrium phases of vapor and liquid at 336.75°C. Answer the questions below by using Appendix A.III of Sandler, "steam table." What is the pressure (MPa) of the PVT cell? The visual window of the PVT cell shows 70 cm³ of vapor and 3 cm³ of liquid at What is the mass of water (a total of liquid water and vapor water) in the PVT cell? Since the water in the PVT cell shows two equilibrium phases at the temperature (and the corresponding pressure you answered in part a), it has no thermodynamic freedom (F = 0). When an additional heat is given to the system while keeping the temperature at 336.75°C and the pressure (that you answered in part a), the volume increases from 73 cm³ to 80 cm³. Note that the system is closed; hence, the total mass of water remains the same as Part b. What is the mass of liquid water, and what is the mass of vapor water? a. b. C. 336.75°C. a. 14 MPa 6₁ v ² = 1.611 cm ³ /g ML 3 cm³ = 1.8629 1.611 cm³/g Mwater = 1.862 g + 6,095g = 7.957g V = 11.485cm ³ /g = 3 my = 70cm³ 11.485 cm³/g = 6.0959
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Can u do part c? I would appreciate if u could check parts a and b. Thanks
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