Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- VCC R2 RC- RI RL R1 RE VEE Assume: B=100, VA=150, Vcc=12V, VEE=GND, Rr=2K, R1=160K, R2=300K, RE=3K, Rc=2.2K, and R1=100K. Convert the circuit to a common-collector circuit. Draw the new circuit (assume the same values for the input and load resistances). Then compute the terminal voltage gain, and Rin (for the whole circuit), re-computing any parameters that you need to solve.arrow_forwardA type II compensator implementation for the above Buck converter is shown below. Ce2 Vout Cet HH Ret Vctrl R2 E/A Vset What should be the voltage Vref in the above type II compensator to produce 5V DC output if R# = 4k and R2=1k. а. Vet b. Write the small signal gain equation (-ctrl) between Vetrl and Vout- out с. Does R2 present in the above gain equation. Please add some explanation. d. How many poles and how many zeros are produced by this type II compensator?arrow_forwardConsider the two-stage amplifier in the figure below. The first stage is a differential amplifier and the second stage is a difference amplifier. Assume that Rg = 20k and you may ignore any early voltage effect. Further assume that Rc = 10k, R3 = 300k and R4 = 100k. What would be the estimated differential gain of the first stage amplifier? CRB close to 200 RB Q4 V01 Stage 1 Q3 O a. O b. close to 150 O c. close to 600 O d. close to 500 e. More information is required to calculate the gain Cm RC Q2 V02 RA R4 R3 Stage 2 -R3 741 + +10v į -10Varrow_forward
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