3. A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocityselector is 3.20 × 103 N/C, while the magnetic field is 0.390 T. When the electric field is turned off, the charged particle travels ona circular path whose radius is 4.00 cm. Find the charge-to-mass ratio of the particle.C/kg

Answered: 3. A charged particle moves through a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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3. A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity
selector is 3.20 × 103 N/C, while the magnetic field is 0.390 T. When the electric field is turned off, the charged particle travels on
a circular path whose radius is 4.00 cm. Find the charge-to-mass ratio of the particle.
C/kg

Expert Solution

Step 1

Electric and magnetic fields in a velocity selector are aligned perpendicular to each other so that only particles on which electric force is equal in magnitude and opposite in direction to the magnetic force could pass through the selector.

This particle must have a specific velocity $ν$ . Otherwise particle will not pass through velocity selector.

F_E= F_M

qE = q $ν$ B

$ν$ = $\frac{E}{B}$ = $\frac{3.20 \times 10^{3}}{0.390}$ = 8.205 $\times$ 10³ m/s

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