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3. ● 4.0m A Y 3.0m B 2.0m 30 25 KN C 2.0m Fixed at A, Hinge at E, Internal Hinge at B, D and F 10 KN/m E 3.0m 3.0m 15 KN 2.0m G

3. ● 4.0m A Y 3.0m B 2.0m 30 25 KN C 2.0m Fixed at A, Hinge at E, Internal Hinge at B, D and F 10 KN/m E 3.0m 3.0m 15 KN 2.0m G

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Pls continue solving in finding the internal reactions. Calculate the reactions at each support. Draw the shear, moment, elastic curve and axial force diagram. ps. Pls write it on a paper and use pythagorean theorem

3.) Fixed at A, Hinge at E, Internal Hinge at B.D.F. 2 GOIN 4.0m <- Ax 8.0m Subst. → Σ ΜΕ ΤΟ G Ay (10) + MA-25 (5) + 15(s) = 0 Ay (10) + MA = 50 MA= 50-10 Ay → RIOM - 4 Ay +50=0 Ay = 12.5 kN @ba - 0 MA= -15 MA- 75 KN.M @ 0 MA = 50-10AY MA= 50-10(12.5) 25 kN ↓c 3 Ay + 4 Ax + (50-10 Ay)-D 3 Ay - 10 Ay +4 Ax +50=0 - TAY + 4 Ax +50=0 (20) Subst → 7 Ay + 4 Ax + (50-10Ay) - 50 7Ay-10Ay +4Ax +50=50 -3Ay + 4 Ax = 0→Ba @2a-3a - TAY SAX50=0 - 3 Ay+gAx=0 -3 Ay+ 4AX=0 -3 (12₁6) + 4 Ax=0 Ax=9,315 kN 2.0m D₂ 3.0m t 10kN/m TEX Fy 3.0m @ AB Ay MA @ A B C D -Ax AAX Ay 15 KN Ja 2.0m B, 4 Bx Toy 25kN C ΣMB- 0 Co³ + Ay (3) + Ax(4) +MA-O 3Ay +4 Ax +MA-0-6 -DX P↑ Dy ZMp=0 C² + Ay(1) + Ax(4) + MA-25 (2)=0 1 Ay+ 4AX + MA= 50 -13
Transcribed Image Text:3.) Fixed at A, Hinge at E, Internal Hinge at B.D.F. 2 GOIN 4.0m <- Ax 8.0m Subst. → Σ ΜΕ ΤΟ G Ay (10) + MA-25 (5) + 15(s) = 0 Ay (10) + MA = 50 MA= 50-10 Ay → RIOM - 4 Ay +50=0 Ay = 12.5 kN @ba - 0 MA= -15 MA- 75 KN.M @ 0 MA = 50-10AY MA= 50-10(12.5) 25 kN ↓c 3 Ay + 4 Ax + (50-10 Ay)-D 3 Ay - 10 Ay +4 Ax +50=0 - TAY + 4 Ax +50=0 (20) Subst → 7 Ay + 4 Ax + (50-10Ay) - 50 7Ay-10Ay +4Ax +50=50 -3Ay + 4 Ax = 0→Ba @2a-3a - TAY SAX50=0 - 3 Ay+gAx=0 -3 Ay+ 4AX=0 -3 (12₁6) + 4 Ax=0 Ax=9,315 kN 2.0m D₂ 3.0m t 10kN/m TEX Fy 3.0m @ AB Ay MA @ A B C D -Ax AAX Ay 15 KN Ja 2.0m B, 4 Bx Toy 25kN C ΣMB- 0 Co³ + Ay (3) + Ax(4) +MA-O 3Ay +4 Ax +MA-0-6 -DX P↑ Dy ZMp=0 C² + Ay(1) + Ax(4) + MA-25 (2)=0 1 Ay+ 4AX + MA= 50 -13
25 KN AM 2.0m A Y 3.0m B 2.0m 3. ● Fixed at A, Hinge at E, Internal Hinge at B, D and F 10 KN/m E 15 KN 3.0m 3.0m 2.0m G
Transcribed Image Text:25 KN AM 2.0m A Y 3.0m B 2.0m 3. ● Fixed at A, Hinge at E, Internal Hinge at B, D and F 10 KN/m E 15 KN 3.0m 3.0m 2.0m G
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