3. (25) A rod of m=4 kg rests on two parallel rails that are L0.8 m apart. Then on the current, so the rod carries a current going between the rails (bottom to top figure, into the page) with a magnitude I 2 A. A uniform magnetic field of mage B 1.5 T pointing downward is applied to the region, as shown in the figure, T moves a distance d= 5 m along the rails in a given time period. Ignore the fricti the rails and the air resistance. L. (a 10) Calculate the magnetic field force F on the rod, and show the direction force on the rod. (b 5) Compute the final velocity of the rod. (c 10) How long does it take the rod to reach this velocity? My answers are My answers (a) Sketch the magnetic fiel d lines in your scratch paper. (b) 1.4. 2. My answers (a) Clockwise (b) Upward 3. My answerS (a) F=2 4N (D. Vf-1.732m/s

A hydrogen ion moves at 6.35 ✕ 10^4 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.25 ✕ 10^−5 T. What is the radius (in m) of the circular path the ion follows?  Mass of hydrogen ion=1.66*10^-27 kg and charge=1.602*10^-19 C.

A thin metal rod that is 1.10 m long has a mass of 58.0 g. What is the minimum current (in A) in the rod that would allow it to levitate above the ground in a uniform magnetic field of magnitude 0.11 T? Round your answer to 2 decimal places.

I am uncertain about parts d and e.

I'm having trouble with some questions. They're listed below. 1) The particle in the figure below has a charge of 8.00 ⨯ 10-6 C, a speed of 1.20 ⨯ 103 m/s, and it is in a uniform magnetic field, directed into the page, of 2.50 ⨯ 10-2 T. The initial velocity of the particle is directed at 30° below the positive x-direction, assuming the x-direction is toward the right. What is the magnitude of the magnetic force acting on the particle?  The image is the first image that shows up with the 9 dots. As for the other question I've already solved for two parts and am just having some trouble for part C.  2) Particle 1 has a charge of +40.0 microcoulombs, and a mass of 2.40 milligrams. Particle 1 also has a speed, when it enters region A, of 6.00 m/s.  a) If region A is a square measuring 30.0 cm on each side (the other regions have the same size as region A, of course), what is the magnitude of the magnetic field in region A- I found it to be 3.6 Teslas b) From the instant particle 1 enters…

An electron ( me = 9.11×1031 kg- q=1.6×10-91 C) moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 7.5 mT. If the speed of the electron is 1.50 x107 m/s, determine the radius of the circular path ( in units of cm). Select one: A. 1.14 B. 0.04 C. 1.67 OD. 0.61 O E. 1.41

A proton, with a charge Q = 1.60 × 10-19 Coulombs has an initial velocity as shown below with a magnitude of v = 2.50 × 105 m/s. Take the proton mass to be M = 1.67 x 10-27 kg. The proton moves in a plane perpendicular to a 3.00 Tesla uniform magnetic field a. Calculate the radius, in meters, of the circular path followed by the proton. With respect to the magnetic field lines, are the orbits in the clockwise or counterclockwise sense? b. Calculate in seconds the amount of time needed for the proton to complete a circu- lar orbit. c. Calculate the frequency in Hertz of the circular orbits.

See the attached figure for this problem. A charge of 7.69 x 10^6 C moves to the right as shown through a region containing both a magnetic field of strength 4.44 T directed into the screen and an electric field of strength 5.51 x 10^5 N/C directed downward. The charge continues through the region at a constant velocity (no acceleration). What is the charge s speed? 3.72E+04 m/s 1.24E+05 m/s 9.92E+04 m/s 6.20E+04 m/s

2. Consider an alpha particle with a charge of +2e. It travels in the -â direction, with a currently unknown ŷ component. It moves with a speed of |ū| = 8.7 × 10® m/s. It is travelling in a uniform magnetic field of magnitude |B| = 2.2 T pointing in the +ŷ direction. Due to the magnetic field, the alpha particle feels a force with magnitude |F| = 3.7 × 10-12 N. Take -ê to be into the page. (a) Using the right hand rule, in what direction is the force pointing? (b) Were the particle an electron, in which direction would the force point? (c) Calculate the velocity component perpendicular to the magnetic field. (Note: Which way is the force pointing? Does this affect the sign of the force?) (d) Find the parallel component of the velocity (Hint: Think trigonom- etry... ) (e) You learn that the alpha particle in fact has a velocity component in the negative ŷ direction. Find the direction, in degrees, that the particle is travelling in.

An oxygen nucleus (8 protons, 8 neutrons) moves at a velocity of 2.39 x 10^6 m/s in a direction perpendicular to a uniform magnetic field. The oxygen nucleus is observed to move in a circular path of radius 1.35 cm. What is the strength of the magnetic field? 1.85 B 3.33 B 4.81 B 3.70 B