(3) Two vertical forces are applied as shown to boom AB which is supported by a ball-and-socket joint at A and cables BC and DE. The weight of the boom is negligible and cable DE is horizontal along the x-axis. Determine the tension forces T1 and T2 in the cables. Ans: T₁ 91.5 kN, T₂ = 53.3 kN 4 m 3 m 4 m T2. D T₁₂ H/2m 3 m 20 kN 30 kN

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A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spriny feet. The ball is started in motion from the equilibrium position with a downward velocity of 6 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second). Suppose that aftert seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second.

A particle moves along the x-axis from x = 8 to x = 29. Find the work done by the force F(x) 4x2 - 6x Note: Write the exact answer not the decimal approximation (for example write not 0.8). Answer: The work done is

Please answer only option b

On the graph to the right, draw a coordinate axis. Draw in the two force vectors. Show by adding the vectors graphically that the net force on the central ring is zero. Verify this algebraically by showing that the sum of the. components is also zero. L +) = N the position. Now, notice that you can slide the ring back and forth along the r axis, placing it at any distance, and the ring will stay in place. This means that every point along the r axis is an equilibrium point. Explain why this is the case. The forces Cancel it does not matter FYEN Now we're going to change the axes. Remove the two pulleys, and place them at angles of 90° and 270°, respectively. Keeping the z axis along = 0, we've now placed the forces along the y axis. Repeat the earlier analysis with the new forces. 1D Trial 2 Results Force Magnitude (N) Direction (6) 0297 F₁ F₂ 0.48A/ 1 80 13 JEN Vector 0.294160 GrMB.NK 1800 F 11800