(3) There is a function void fnE(int i, int num) that runs in 1000-i steps, regardless of what num is. Consider the following code snippet: void fnA(int S[]) { int n = s.length; for (int i=0;i
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![(3) There is a function void fnE(int i, int num) that runs in 1000-i steps, regardless of what
num is. Consider the following code snippet:
void fnA(int S[]) {
S.length;
for (int i=0;i<n;i++) {
fnE(i, S[i]);
int n =
}
}
What's the running time in Big-O of fnA as a function of n, which is the length of the array S. You
should assume that it takes constant time to determine the length of an array.
(4) Show that h(n) = 16n2 + 1ln* +0.1n³ is not O(n“).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70a6ff50-f1d8-4b72-a2e2-21ac132708c4%2F4ea8eb57-14b9-48b0-a1a8-ad9a6f21ee71%2Fk29iqr9_processed.png&w=3840&q=75)
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- Q1. 1 and 2void find and replace (char A, char *oldc, char "newc) [ tor (int i-0; i<5; i++) for (int j-0; j<3; j++) if (A[i) == oldc[jl) A[i] = newe[jl; The procedure is tested with the following four test cases. 1. oldc "abc", newc = "dab" 2. oldc "cde", newc = "bcd" 3. oldc "bca", newc= "cda" 4. oldc "abc", newc = "bac" 27Please define and initialize and array X of length 8. You need implement following and write outcomes with reasons; 1.cout<< X+1; 2.cout<<&X+1; 3.cout<<2[X]; 4.cout<<&X[0]+1; 5.cout<<*(X+1); 6.cout<<*X+1; Also, practice and play with pointers using multiplication, division, subtraction and addition. You may also play with it your ways and find out reasoning. Write down those reasoning.
- Q1. 5 and 6 subparts only if you do both then only I will provide upvotePLEASE HELP!5. What is wrong with the following function and why? int *setup(int n){ int a[n); for(int i=0; iImplement in C Programming 6.11.2: Modify an array parameter. Write a function SwapArrayEnds() that swaps the first and last elements of the function's array parameter. Ex: sortArray = {10, 20, 30, 40} becomes {40, 20, 30, 10}. #include <stdio.h> /* Your solution goes here */ int main(void) { const int SORT_ARR_SIZE = 4; int sortArray[SORT_ARR_SIZE]; int i; int userNum; for (i = 0; i < SORT_ARR_SIZE; ++i) { scanf("%d", &sortArray[i]); } SwapArrayEnds(sortArray, SORT_ARR_SIZE); for (i = 0; i < SORT_ARR_SIZE; ++i) { printf("%d ", sortArray[i]); } printf("\n"); return 0;}Answer it is c++ only Chef recorded a video explaining his favorite recipe. However, the size of the video is too large to upload on the internet. He wants to compress the video so that it has the minimum size possible. Chef's video has N frames initially. The value of the th frame is A₁. Chef can do the following type of operation any number of times: • Choose an index i (1 ≤ i ≤ N) such that the value of the ith frame is equal to the value of either of its neighbors and remove the ith frame. Find the minimum number of frames Chef can achieve. Input 1 1 5 output 14. Please explain the spatial and temporal locality in general. Please identify and explain the localities in the following example.- int a[N]; For (i 0; iA piece of programm code is given:int A[1200];...int find_in_arr(int * A, int x){ int found = 0;for(i = 0; i<1200; i++) if(A[i] == x) { found++; break } if ( found == 0) return 0;return 1;}- please optimize the code to run faster by using a barrierWrite a parallel program for the following code /* PROGRAM Sieve */ #include <stdlib.h> #include <math.h> #define n 100 boolean Prime[n+1]; int i,num,loc; main( ) { for (i = 1; i <= n; i++) Prime[i] = TRUE; for (num = 2; num <= Sqrt(n); num++) if (Prime[num]) { loc = num + num; while (loc <= n) { Prime[loc] = False; } } loc = loc + num; }For each of the following function, indicate the class (n) the function belongs (use the simplest g (n) possible in your answer. a) (n² + 5)1⁰ c) 5n+3 + 7+1 b) 4nlog2(n+2)² + (n+2)³log2(n/2) d) 2n + 3n+ n²+ 4nRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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