3 NEXT > < PREV 1 2 Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = = 6.3 × 10-5 RESET [0] [21.5] [37.7] [0.176] [0.261] [0.880] [1.31] [0.178] [0.888] [x] [2x] [21.5-x] [37.7+x] [0.176-x] [0.261 + x] [0.880 - x] [1.31 + x] [0.178 + x] [0.888 + x] < PREV 1 2 3 Based on your ICE table (Part 1) and the equilibrium expression for Ka (Part 2), determine the pH of the buffer solution. pH = RESET 0 4.2 x 10-5 6.23 4.37 2.4 × 10-11 7.77 9.63 0.880 Determine the pH of a buffer solution by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka for HC7H5O2 is 6.3 × 10-5. Complete Parts 1-3 before submitting your answer. 1 2 3 NEXT > The buffer was prepared by dissolving 21.5 g HC-H5O2 and 37.7 g of NaC7H5O2 in 200.0 mL of solution. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) 0.178 HC7H5O2(aq) + H₂O(1) = H3O+(aq) + C7H5O2-(aq) 0 21.5 37.7 0.176 0.261 0.888 +x -x 0.880 - x 1.31 + x 0.178 + x 0.888 + x 0.880 RESET 1.31 21.5-x 37.7 + x 0.176 - x 0.261 + x
3 NEXT > < PREV 1 2 Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = = 6.3 × 10-5 RESET [0] [21.5] [37.7] [0.176] [0.261] [0.880] [1.31] [0.178] [0.888] [x] [2x] [21.5-x] [37.7+x] [0.176-x] [0.261 + x] [0.880 - x] [1.31 + x] [0.178 + x] [0.888 + x] < PREV 1 2 3 Based on your ICE table (Part 1) and the equilibrium expression for Ka (Part 2), determine the pH of the buffer solution. pH = RESET 0 4.2 x 10-5 6.23 4.37 2.4 × 10-11 7.77 9.63 0.880 Determine the pH of a buffer solution by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka for HC7H5O2 is 6.3 × 10-5. Complete Parts 1-3 before submitting your answer. 1 2 3 NEXT > The buffer was prepared by dissolving 21.5 g HC-H5O2 and 37.7 g of NaC7H5O2 in 200.0 mL of solution. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) 0.178 HC7H5O2(aq) + H₂O(1) = H3O+(aq) + C7H5O2-(aq) 0 21.5 37.7 0.176 0.261 0.888 +x -x 0.880 - x 1.31 + x 0.178 + x 0.888 + x 0.880 RESET 1.31 21.5-x 37.7 + x 0.176 - x 0.261 + x
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.29P: 7-29 The following reaction was allowed to reach equilibrium at 25°C. Under each component is its...
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![3
NEXT >
< PREV
1
2
Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in
order to determine the unknown. Each reaction participant must be represented by one
tile. Do not combine terms.
Ka
=
= 6.3 × 10-5
RESET
[0]
[21.5]
[37.7]
[0.176]
[0.261]
[0.880]
[1.31]
[0.178]
[0.888]
[x]
[2x]
[21.5-x]
[37.7+x]
[0.176-x]
[0.261 + x]
[0.880 - x]
[1.31 + x]
[0.178 + x]
[0.888 + x]
< PREV
1
2
3
Based on your ICE table (Part 1) and the equilibrium expression for Ka (Part 2),
determine the pH of the buffer solution.
pH
=
RESET
0
4.2 x 10-5
6.23
4.37
2.4 × 10-11
7.77
9.63
0.880](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff922ab2d-c754-4c9c-9d3b-bd784fecfd89%2Faf4a575e-20e3-4464-958b-86ac16cd4d5c%2Fvrawoh_processed.png&w=3840&q=75)
Transcribed Image Text:3
NEXT >
< PREV
1
2
Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in
order to determine the unknown. Each reaction participant must be represented by one
tile. Do not combine terms.
Ka
=
= 6.3 × 10-5
RESET
[0]
[21.5]
[37.7]
[0.176]
[0.261]
[0.880]
[1.31]
[0.178]
[0.888]
[x]
[2x]
[21.5-x]
[37.7+x]
[0.176-x]
[0.261 + x]
[0.880 - x]
[1.31 + x]
[0.178 + x]
[0.888 + x]
< PREV
1
2
3
Based on your ICE table (Part 1) and the equilibrium expression for Ka (Part 2),
determine the pH of the buffer solution.
pH
=
RESET
0
4.2 x 10-5
6.23
4.37
2.4 × 10-11
7.77
9.63
0.880
Transcribed Image Text:Determine the pH of a buffer solution by constructing an ICE table,
writing the equilibrium constant expression, and using this information to
determine the pH. The Ka for HC7H5O2 is 6.3 × 10-5. Complete Parts 1-3
before submitting your answer.
1
2
3
NEXT >
The buffer was prepared by dissolving 21.5 g HC-H5O2 and 37.7 g of NaC7H5O2 in 200.0
mL of solution. Fill in the ICE table with the appropriate value for each involved species
to determine concentrations of all reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
0.178
HC7H5O2(aq)
+
H₂O(1)
=
H3O+(aq)
+
C7H5O2-(aq)
0
21.5
37.7
0.176
0.261
0.888
+x
-x
0.880 - x
1.31 + x
0.178 + x
0.888 + x
0.880
RESET
1.31
21.5-x
37.7 + x
0.176 - x
0.261 + x
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