3) Find I, in the circuit below 6 mA 12 V 2 mA 2 k2 4 KS2
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- Find the following with complete solution and formula RT IT E1 E2 E3 E4 I1 I2 I3 I4The currents at the junction point in a circuit have the following values I1 = (15 - j4) A and l2 = (12 + j22) A. Calculate l1 + l2Part B Given the following circuit F1 SW1 SW2 Sw3 SW4 SW5 SW6 BAT1 R1 R2 R3 R4 R5 R6 12 V 12 0 24 0 48 0 00
- find the current of loop 1 R6 · 150 R1 R3 180 200 R8 loop1 140 R5 =25V 0.757 0577 0.755A 4.5MF Copacitor to a 74 K A Arilo ohms resistor with ç=20ov. initially unchucged is connected and an emf sourse 1) current in th Ac Circvit immediatlu of ter Saritch s clored?: b)cuirentin Ke ciccuit AMor vera long time after Switch s closed> ) what is te Charge On the copurilor ofter a verq long time atter the Sw/tch s i's clordi 1 How long After the Smitch is Closed (cached 50%0 has the coporitm of idy Pinal voltage.Use Kirchhoff's Law to solve for the current passing through each resistor. Compare it with what you got from the PHET Simulation A D 392 www 6V E www F 192 www 292 352 www 9V B C
- PROBLEM 4 Find Req R2 R3 120 R4: 60 R5 R7: 30 60 R1 120: Reg R6 180 Figure 4Each of the cells shown in the figure has an emf of 1.50 V and a 0.0750-ohm internalresistance. Find I1, I2, and I3.8-Find Leq at the terminals a-b of the circuit below. 6 mH 8 mH ell 5 mH le a 12 mH 8 mH 6 mH 4 mH ell 8 mH b ll 10 mH ll ll ll
- Create this circuit in tinker caduse, Resistors, powersupply, and multimeter if possiblecomputational answers:( i have already solved this using mesh analysis i just need the simulation in tinker cad that shows this answers in the powersupply) Ia=0.1441 AIb=0.2 AIc=0.01162 AFind the Thevinin equivalent circuit for the circuit shown below and redraw it with the values of Rand Eth 412A R₁ 492 R₂ 292 Figure (9) a R3 b @ 792 Noidentify the minterms that corresponds to the f and d below. Please be sure you know how to solve correctly and show work. I will also provide an image that states what the answer is without showing work I need to see work and explained how to get there. f=b'c'd' + abd' + abd d=a'c'd + b'cd'