3) Extra Credit Challenge: We have seen in class that the Poisson distribution with parameter A = np is a good approximation to the probability distribution of the number of successes in n independent trials when each trial has probability p of being a success, provided that n is large and p small. In fact, the Poisson distribution remains a good approximation even when the trials are not independent, provided that their dependence is weak. Furthermore, it is not required that each trial be identical. For example, if the i-th trial had a probability p; of being a success (i =1, 2,...,n), then the total number of successes that occur in the n trials is well approximated by a Poisson random variable with A = n E, Pi, if each Pi is "small" and each trial is independent or only "weakly dependent." This is called the Poisson paradigm, . Suppose an experiment has n identical and independent trials, with each trial having k possible outcomes with probabilities p1,..., Pk respectively. Using the Poisson paradigm, show that if all the p;'s are small then the probability that no trial outcome occurs more than once is approximately equal to exp(-n(n – 1) E=, P /2).

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3) Extra Credit Challenge: We have seen in class that the Poisson distribution with parameter A = np is
a good approximation to the probability distribution of the number of successes in n independent trials when each
trial has probability p of being a success, provided that n is large and p small. In fact, the Poisson distribution
remains a good approximation even when the trials are not independent, provided that their dependence is weak.
Furthermore, it is not required that each trial be identical. For example, if the i-th trial had a probability p; of
being a success (i = 1,2, ...,n), then the total number of successes that occur in the n trials is well approximated
by a Poisson random variable with A = n E, Pi, if each Pi is "small" and each trial is independent or only
"weakly dependent." This is called the Poisson paradigm, .
Suppose an experiment has n identical and independent trials, with each trial having k possible outcomes with
probabilities p1,...,Pk respectively. Using the Poisson paradigm, show that if all the p,'s are small then the
probability that no trial outcome occurs more than once is approximately equal to exp(-n(n – 1)E P/2).
Transcribed Image Text:3) Extra Credit Challenge: We have seen in class that the Poisson distribution with parameter A = np is a good approximation to the probability distribution of the number of successes in n independent trials when each trial has probability p of being a success, provided that n is large and p small. In fact, the Poisson distribution remains a good approximation even when the trials are not independent, provided that their dependence is weak. Furthermore, it is not required that each trial be identical. For example, if the i-th trial had a probability p; of being a success (i = 1,2, ...,n), then the total number of successes that occur in the n trials is well approximated by a Poisson random variable with A = n E, Pi, if each Pi is "small" and each trial is independent or only "weakly dependent." This is called the Poisson paradigm, . Suppose an experiment has n identical and independent trials, with each trial having k possible outcomes with probabilities p1,...,Pk respectively. Using the Poisson paradigm, show that if all the p,'s are small then the probability that no trial outcome occurs more than once is approximately equal to exp(-n(n – 1)E P/2).
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