3 attempts left Check my work Enter your answer in the provided box. Find AG for the following reaction, at 25°C, using AH and values. NH,CI(s) → NH3(g) + HCI(g) kJ Standard Thermodynamic Values at 298 K Substance or Ion AH (kJ/mol) f (J/mol K) HCI(g) HCI(aq) NH3(g) - -92.3 186.79 -167.46 55.06 -45.9 193 NH3(aq) NH,CI(s) -80.83 110 -314.4 94.6

3 attempts left Check my work Enter your answer in the provided box. Find AG for the following reaction, at 25°C, using AH and values. NH,CI(s) → NH3(g) + HCI(g) kJ Standard Thermodynamic Values at 298 K Substance or Ion AH (kJ/mol) f (J/mol K) HCI(g) HCI(aq) NH3(g) - -92.3 186.79 -167.46 55.06 -45.9 193 NH3(aq) NH,CI(s) -80.83 110 -314.4 94.6

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

rch Z The change in enthalpy and entropy for a certain reaction are -16.3 kJ/mol and 112 J/K.mol, respectively. Using the equations below, and assuming standard state conditions (25°C), calculate AG and select the answer from the options below: F2 AG=AH - TASⓇ, AG=-RT In Keq, ΔΗΘ Ase RT R In Keq == O-17.1 kJ/mol O-49.7 kJ/mol O-19.1 kJ/mol O-2816.3 J/mol O-33392 J/mol DII F3 Bi F4 % 130 F6 & 88 PrtScn F8 20°C Home
Consider the reaction Co(g) + H20(1) CO2(g) + H2(g) Calculate the standard Gibbs free energy change for this reaction at 25°C from AHOxn and ASOrxn: kJ/mol AG°rxn =
One of the reactions that destroys ozone in the upper atmosphere is NO(9) + O3 (g) = NO2(g) + O2(9) Calculate AG° and K (at 298 K) for this reaction. Substance and State AG¡' (kJ/mol) NO(g) NO2(9) 02(9) 03(9) 87 52 163 AG kJ K=
Using enthalpies of formation, calculate AH for the following reaction at 25°C. Also calculate AS" for this reaction from standard entropies at 25°C. Use these values to calculate AG" for the reaction at this temperature. C,H4 (9) + 302(9) → 2C02(9) + 2H2O(9) Species AH; (k/mol) S" (J/mol K) C,H (9) O2 (9) 52.47 219.2 205.0 -393.5 213.7 CO2(9) H,O(g) -241.8 188.7 AH" = kJ AS - J/K AG" - kJ
2. Standar... 1req Question O Question Question 3. AS surrou 1req 4. AG° =A... 1req 5. AG: Pre... 1req Consider the reaction: P4010 (8) + 6H2O(l) → 4H3PO4(aq) Using standard absolute entropies at 298 K, calculate the entropy change for the system when 1.80 moles of P4010 (8) react at standard conditions. J 6. AG: Ent... 1req Substance STO K.mol 7. AG fro... 1req H3PO4(aq) 158.0 P4010(s) 228.9 8. Calculat... 1req H2O(l) 69.9 9. Calculat... 1req AS° = system J/K 10. Calcul... 1req
alculate AG at 298 K for the reaction Cs, (1) + 30, (g) – CO,(g) + 2 SO, (g) ased on these reactions. C(3) + 0,(g) → Co, (g) AG = -39728 kJ/mol S(3) + 0,(g) → S0,() AG=-300.19 kJ/mol C(s) + 2S(s) CS, (1) AG = +62.37 kJ/mol AG = kJ/mol
I was able to understand and do the first question but for some reason, I'm stumped on the second and third question.
True/False
mited States) not enough information. Using the general properties of Gibbs free energy The standard reaction free energy AG = -835. kJ for this reaction: 2 Al(s) + Fe₂O3(s)-Al₂O3(s) + 2 Fe(s) Use this information to complete the table below. Round each of your answers to the nearest kJ. reaction Al₂O3(s) + 2 Fe(s)-2Al(s) + Fe₂O3(s) Al(s) + Fe₂O,(s)-Al₂O₂(s) + Fe(s) AL₂O3(s) - Fe(s) Al(s) + Fe₂O₂ (s) kJ AGO KJ MacBook Air Focus E E
Which one of the following reactions cannot proceed spontaneously as written at any temperature? Assume that AHn does not depend on temperature. O A 20(s) + 2S(s) + Oz(g) 20OS(g) AH pn =-137 kJ B. 302(9) 201(9) AH on = +284 kJ C. COC(9) Co(g) • Ch(9) AH pn+112 kJ D. N,0,(9) 2NO,(g) AHn=+171 kJ E. 2C20(9) 2C2(g) + O2(9) AH pen =-151 kJ
Calculate the equilibrium constant at 25°C for each equilibrium reaction and comment on the extent of the reaction. 1. 2KCIO:(s) = 2KCI(s) + 302(g); AG -225.8 kJ/mol = 2. COCI2(s) + 6 H20(1) =6C0C12-6 H20(s); AHxn°= -352 kJ/mol, ASpxn°= -899 J/(mol·K) 3. PCl3(g) + O2(g) = 2POCI3(g); (PC3); AGP(PCl3)= -272.4 k]/mol, AGP(POCI3) = -558.5 kJ/mol %3D
Calculate the equilibrium constant at 25 degrees C for each of the following reactions from the value of change in G degrees given I2(s) + Cl2(g) 2ICl9(g) change in free energy =-10.88kJ H2(g0 +I2(s) 2HI(g) change ing free energy= 3.4kJ