(3) (4) (5) day dt4 - y = 0 d²u du +3 dt² dt d²y dy dx² + dx - +3u = 6e-2t 2y = 4x² (Note that the right-hand side is 2nd order polynomial. Use the general form of 2nd order polynomial ax²+bx+c as a trial solution.)
(3) (4) (5) day dt4 - y = 0 d²u du +3 dt² dt d²y dy dx² + dx - +3u = 6e-2t 2y = 4x² (Note that the right-hand side is 2nd order polynomial. Use the general form of 2nd order polynomial ax²+bx+c as a trial solution.)
(3) (4) (5) day dt4 - y = 0 d²u du +3 dt² dt d²y dy dx² + dx - +3u = 6e-2t 2y = 4x² (Note that the right-hand side is 2nd order polynomial. Use the general form of 2nd order polynomial ax²+bx+c as a trial solution.)
Find the general solution of the following linear differential equations.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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