3 + +++ -2 -3 -4 The graph above shows the base of an object. Compute the exact value of the volume of the object, given that cross sections (perpendicular to the base) are isosceles right triangles with their hypotenuse in the base. V = 91 112π 3 X

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter9: Surfaces And Solids
Section9.3: Cylinders And Cones
Problem 25E
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U
5
4
MI
3
2
-2
-3
-5
2
V =
4
112π
3
6
The graph above shows the base of an object. Compute the exact value of the volume of the object, given
that cross sections (perpendicular to the base) are isosceles right triangles with their hypotenuse in the base.
9 1
X
Transcribed Image Text:U 5 4 MI 3 2 -2 -3 -5 2 V = 4 112π 3 6 The graph above shows the base of an object. Compute the exact value of the volume of the object, given that cross sections (perpendicular to the base) are isosceles right triangles with their hypotenuse in the base. 9 1 X
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