= −2y + 4)(¹) ► (v − 2) |___2y−2 -2y+4)² (3²-2y+4)² Oor is undefined. g'(y) is undefined where the quadratic y2-2y+4 in the denominator is 0. The discriminant for y2-2y+ 4 is -12 2y-2 -12 =) ere are no real roots for y2 - 2y + 4, and so g(y) exists for all real numbers. This means critical numbers occur where 0 = g'(x) = y(4-y) (²-2y+4)² This happens only when the numerator equals 0. Thus,

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Tutorial Exercise
Find the critical numbers of the function.
y-2
y²-2y + 4
Part 1 of 3
For g(y) =
Part 2 of 3
g(y) =
Part 3 of 3
y-2
y2-2y + 4
g'(y) =
2
1
numbers are
y =
y =
we have
- 2y + 4
y² - 2y +4 (1) - (y-2)
-2y+4)2
Critical numbers occur where g'(y) equals 0 or is undefined. g'(y) is undefined where the quadratic y² - 2y + 4 in the denominator is 0. The discriminant for y² - 2y + 4 is
-2 2-4(1)(4
(smaller value)
(larger value)
Submit Skip (you cannot come back)
2y - 2
4) = -12
(y² - 2y + 4)²
y(4-y)
Since the discriminant is negative, then there are no real roots for y² - 2y + 4, and so g'(y) exists for all real numbers. This means critical numbers occur where 0 = g'(x) = √₁² - 2y + 412. This happens only when the numerator equals 0. Thus, the critical
2y - 2
-12
Transcribed Image Text:Tutorial Exercise Find the critical numbers of the function. y-2 y²-2y + 4 Part 1 of 3 For g(y) = Part 2 of 3 g(y) = Part 3 of 3 y-2 y2-2y + 4 g'(y) = 2 1 numbers are y = y = we have - 2y + 4 y² - 2y +4 (1) - (y-2) -2y+4)2 Critical numbers occur where g'(y) equals 0 or is undefined. g'(y) is undefined where the quadratic y² - 2y + 4 in the denominator is 0. The discriminant for y² - 2y + 4 is -2 2-4(1)(4 (smaller value) (larger value) Submit Skip (you cannot come back) 2y - 2 4) = -12 (y² - 2y + 4)² y(4-y) Since the discriminant is negative, then there are no real roots for y² - 2y + 4, and so g'(y) exists for all real numbers. This means critical numbers occur where 0 = g'(x) = √₁² - 2y + 412. This happens only when the numerator equals 0. Thus, the critical 2y - 2 -12
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