2x + 4 h(x) = 1 2x 1 f (x) = 1 –x g(x) = 3( x + 2x 6. | 3 -- 8. a.lim -4 · f (x) d.lim (8 · f(x) – g(x) – 2 · h(x)) X→2 x→2 b.lim (g(x) – h(x)) e.lim (-2· f(x) + 4 • g(x) + 2 · h(x)) X→2 X→2 c.lim (4 · f(x) + h(x)) f.lim f(x) + g(x) + 2 · h(x)) 3 X→2 X→2 +

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Type exact answer only. No other unnecessary symbols or words. Write DNE if you think the limit does not exist.

answer F only

 

АCTIVITY
GIVEN :
2x
+ 4 h(x) =
2x
1
2х +
3
1
f (x) = 1 –x
8
g(x) = 3(x +
a.lim -4 · f (x)
X→2
d.lim (8 · f(x) – g(x) – 2 · h(x))
|
X→2
b.lim (g(x) – h(x))
e.lim (-2· f(x) + 4 • g(x) + 2 · h(x))
X→2
X→2
c.lim (4 · f (x) + h(x))
.3
f.lim G f(x) + g(x)+ 2· h(x))
X→2
X→2 `2
3
Transcribed Image Text:АCTIVITY GIVEN : 2x + 4 h(x) = 2x 1 2х + 3 1 f (x) = 1 –x 8 g(x) = 3(x + a.lim -4 · f (x) X→2 d.lim (8 · f(x) – g(x) – 2 · h(x)) | X→2 b.lim (g(x) – h(x)) e.lim (-2· f(x) + 4 • g(x) + 2 · h(x)) X→2 X→2 c.lim (4 · f (x) + h(x)) .3 f.lim G f(x) + g(x)+ 2· h(x)) X→2 X→2 `2 3
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