(^ + 2)x, 2х, + 3x, — 0 - 2x, + (1 – 1)x, + 6xz = 0 2x2 + Ax3 = 0 X, +

Solve the following homogeneous system of linear equations: x1+x2+x3-2x4 = 0 -3x1-3x2+2x3-9x4 = 0 -3x1-3x2-2x3+6x4 = 0 -x1-x2-3x3+7x4 = 0 -2x1-2x2-x3-2x4 = 0 If the system has no solution, demonstrate this by giving a row-echelon form of the augmented matrix for the system. You can resize a matrix (when appropriate) by clicking and dragging the bottom-right corner of the matrix. The system has infinitely many solutions The system has no solution The system has a unique solution The system has infinitely many solutions x2 = 0 + s0 X3

The nonlinear system has six real solutions. 4x0 x₁ + x₂ = X0X3 xo - 2x₁ + 3x₂ = x₂x3 -xo + 3x₁ - 2x₂ = X₁ X3 x² + x² + x² = 1 (a) Show that if (x0, X₁, X2, X3)T is a solution, then (-X0, −X₁, −X₂, X3)¹ is also a solution.