2H+ (aq) + Sn(s) → H₂ (9) + Sn²+ (aq) 2H+ (aq) + 2e → H2 (9) Ere = 0.000 V Sn2+(aq) + 2e → Sn(s) Eve = -0.140 V red Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGº for this reaction would be [ than zero.

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2H+ (aq) + Sn(s) → H₂ (9) + Sn²+ (aq)
2H+ (aq) + 2e → H2 (9) Ere
= 0.000 V
Sn2+(aq) + 2e → Sn(s) Eve
= -0.140 V
red
Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm.
Equilibrium constant at 298 K:
AGº for this reaction would be [
than zero.
Transcribed Image Text:2H+ (aq) + Sn(s) → H₂ (9) + Sn²+ (aq) 2H+ (aq) + 2e → H2 (9) Ere = 0.000 V Sn2+(aq) + 2e → Sn(s) Eve = -0.140 V red Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGº for this reaction would be [ than zero.
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