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2a+3c=5a+2c=1 There is an ordered pair that is the solution of the system of equations shown. The value of one of the variables in the solution of the system can be obtained by using which of the following substitutions?     2(2c−1)+3c=5, because a=2c−1. 2 times, open parenthesis, 2 c minus 1, close parenthesis, plus 3 c, equals 5 , because a, equals 2 c minus 1 . A 2(1−2c)+3c=5, because a=1−2c. 2 times, open parenthesis, 1 minus 2 c, close parenthesis, plus 3 c, equals 5 , because a, equals 1 minus 2 c . B 2a+3(a−1)=5, because c=a−1. 2 a, plus, 3 times, open parenthesis, a, minus 1, close parenthesis, equals 5 , because c equals a, minus 1 . C 2a+3(1−a)=5, because c=1−a. 2 a, plus 3 times, open parenthesis, 1 minus a, close parenthesis, equals 5 , because c equals, 1 minus a . D

2a+3c=5a+2c=1 There is an ordered pair that is the solution of the system of equations shown. The value of one of the variables in the solution of the system can be obtained by using which of the following substitutions?     2(2c−1)+3c=5, because a=2c−1. 2 times, open parenthesis, 2 c minus 1, close parenthesis, plus 3 c, equals 5 , because a, equals 2 c minus 1 . A 2(1−2c)+3c=5, because a=1−2c. 2 times, open parenthesis, 1 minus 2 c, close parenthesis, plus 3 c, equals 5 , because a, equals 1 minus 2 c . B 2a+3(a−1)=5, because c=a−1. 2 a, plus, 3 times, open parenthesis, a, minus 1, close parenthesis, equals 5 , because c equals a, minus 1 . C 2a+3(1−a)=5, because c=1−a. 2 a, plus 3 times, open parenthesis, 1 minus a, close parenthesis, equals 5 , because c equals, 1 minus a . D

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.7: Puzzle Problems
Problem 19P
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2a+3c=5a+2c=1

There is an ordered pair that is the solution of the system of equations shown. The value of one of the variables in the solution of the system can be obtained by using which of the following substitutions?

 
 

  • 2(2c−1)+3c=5, because a=2c−1.

    2 times, open parenthesis, 2 c minus 1, close parenthesis, plus 3 c, equals 5 , because a, equals 2 c minus 1 .
    A

  • 2(1−2c)+3c=5, because a=1−2c.

    2 times, open parenthesis, 1 minus 2 c, close parenthesis, plus 3 c, equals 5 , because a, equals 1 minus 2 c .
    B

  • 2a+3(a−1)=5, because c=a−1.

    2 a, plus, 3 times, open parenthesis, a, minus 1, close parenthesis, equals 5 , because c equals a, minus 1 .
    C

  • 2a+3(1−a)=5, because c=1−a.

    2 a, plus 3 times, open parenthesis, 1 minus a, close parenthesis, equals 5 , because c equals, 1 minus a .
    D
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