29. Solve problems using Boyle's, Charles's, or the Combined gas law, such as those below. a. A sample of gas is contained in a flexible container at 2.51 atm. The container expands to 3.5 L as the pressure decreases to 1.89 atm. What was the original volume? b. Originally, a balloon has a volume of 0.302 L at 1.53 atm and 25.7°C. The balloon expands until the final volume is 0.594 L at a pressure of 0.892 atm. What is the final temperature of the balloon?

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### Solving Gas Law Problems: Boyle's, Charles's, and Combined Gas Law

#### Problem 29

**Solve problems using Boyle's, Charles's, or the Combined gas law, such as those below.**

**a. Sample Gas Problem (Boyle's Law)**

A sample of gas is contained in a flexible container at \(2.51 \, \text{atm}\). The container expands to \(3.5 \, \text{L}\) as the pressure decreases to \(1.89 \, \text{atm}\). What was the original volume?

**b. Balloon Expansion Problem (Combined Gas Law)**

Originally, a balloon has a volume of \(0.302 \, \text{L}\) at \(1.53 \, \text{atm}\) and \(25.7^\circ \text{C}\). The balloon expands until the final volume is \(0.594 \, \text{L}\) at a pressure of \(0.892 \, \text{atm}\). What is the final temperature of the balloon?

### Explanation of Relevant Gas Laws

**Boyle's Law:**
\[ P_1V_1 = P_2V_2 \]
(At constant temperature, the pressure of a gas is inversely proportional to its volume.)

**Charles's Law:**
\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]
(At constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin.)

**Combined Gas Law:**
\[ \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \]
(The relationship between pressure, volume, and temperature of a fixed amount of gas.)

### Detailed Solution Approach

**a. For Boyle's Law Problem:**

Given:
- \( P_1 = 2.51 \, \text{atm} \)
- \( P_2 = 1.89 \, \text{atm} \)
- \( V_2 = 3.5 \, \text{L} \)

Need to find \( V_1 \):

Using Boyle's Law:
\[ P_1V_1 = P_2V_2 \]

\[ V_1 = \frac{P_2V_2}{P_1} \
Transcribed Image Text:### Solving Gas Law Problems: Boyle's, Charles's, and Combined Gas Law #### Problem 29 **Solve problems using Boyle's, Charles's, or the Combined gas law, such as those below.** **a. Sample Gas Problem (Boyle's Law)** A sample of gas is contained in a flexible container at \(2.51 \, \text{atm}\). The container expands to \(3.5 \, \text{L}\) as the pressure decreases to \(1.89 \, \text{atm}\). What was the original volume? **b. Balloon Expansion Problem (Combined Gas Law)** Originally, a balloon has a volume of \(0.302 \, \text{L}\) at \(1.53 \, \text{atm}\) and \(25.7^\circ \text{C}\). The balloon expands until the final volume is \(0.594 \, \text{L}\) at a pressure of \(0.892 \, \text{atm}\). What is the final temperature of the balloon? ### Explanation of Relevant Gas Laws **Boyle's Law:** \[ P_1V_1 = P_2V_2 \] (At constant temperature, the pressure of a gas is inversely proportional to its volume.) **Charles's Law:** \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] (At constant pressure, the volume of a gas is directly proportional to its temperature in Kelvin.) **Combined Gas Law:** \[ \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \] (The relationship between pressure, volume, and temperature of a fixed amount of gas.) ### Detailed Solution Approach **a. For Boyle's Law Problem:** Given: - \( P_1 = 2.51 \, \text{atm} \) - \( P_2 = 1.89 \, \text{atm} \) - \( V_2 = 3.5 \, \text{L} \) Need to find \( V_1 \): Using Boyle's Law: \[ P_1V_1 = P_2V_2 \] \[ V_1 = \frac{P_2V_2}{P_1} \
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