Similar to linear kinetic energy, rotational kinetic energy depends on the moment of inertia I and the square of the angular velocity ω as K=1/2Iω2. When the moment of inertia and/or the angular velocity changes, the new rotational kinetic energy is just the original multiplied by a factor mm, such that Knew=mK. What is the multiplication factor mm when the moment of inertia increases to 21I and the angular velocity reduces to 0.2ω? Give the formula first then solve. 29.)Similar to linear kinetic energy, rotational kinetic energy depends on the moment of inertia I andthe square of the angular velocity w asWhen the moment of inertia and/or the angular velocity changes, the new rotational kinetic energy isjust the original multiplied by a factor mm, such thatKnew=mK.What is the multiplication factor mm when the moment of inertia increases to 211 and the angularvelocity reduces to 0.2w?

The rotational KE is given by K=12Iω2 If I'=21Iω'=0.2ω Then the new KE becomes…

29.) Similar to linear kinetic energy, rotational kinetic energy depends on the moment of inertia I and the square of the angular velocity o as When the moment of inertia and/or the angular velocity changes, the new rotational kinetic energy is just the original multiplied by a factor mm, such that Knew=mK. What is the multiplication factor mm when the moment of inertia increases to 211 and the angular velocity reduces to 0.20?

29.) Similar to linear kinetic energy, rotational kinetic energy depends on the moment of inertia I and the square of the angular velocity o as When the moment of inertia and/or the angular velocity changes, the new rotational kinetic energy is just the original multiplied by a factor mm, such that Knew=mK. What is the multiplication factor mm when the moment of inertia increases to 211 and the angular velocity reduces to 0.20?