Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Topic: Exact DE please answer number 28
= 1. 24. (1 − xy)−² dx + [y² + x²(1 − xy)¯²] dy = 0; when x = 4, y = ANS. xy4y³ + 3xy − 3x − 3 = 0. 25. (ye*y – 2y³) dx + (x ex − 6xy² – 2y) dy = 0; when x = 0, y = 2. ANS. exy = 2xy³ + y² – 3. 26. (3 + y + 2y² sin² x) dx + (x + 2xy − y sin 2x) dy = 0. ANS. y² sin 2x = c + 2x(3 + y + y²). 27. 2x[3x + y − y exp (−x²)] dx + [x² + 3y² + exp(-x²)] dy = 0. 28. (xy² + x - 2y + 3) dx + x²y dy = 2(x + y) dy; when x ANS. (xy — 2)² + (x + 3)² = 2y² + 15. ANS. x²y + y² + 2x³ + y exp (− x²) = c. 1, y = 1. =
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Transcribed Image Text:= 1. 24. (1 − xy)−² dx + [y² + x²(1 − xy)¯²] dy = 0; when x = 4, y = ANS. xy4y³ + 3xy − 3x − 3 = 0. 25. (ye*y – 2y³) dx + (x ex − 6xy² – 2y) dy = 0; when x = 0, y = 2. ANS. exy = 2xy³ + y² – 3. 26. (3 + y + 2y² sin² x) dx + (x + 2xy − y sin 2x) dy = 0. ANS. y² sin 2x = c + 2x(3 + y + y²). 27. 2x[3x + y − y exp (−x²)] dx + [x² + 3y² + exp(-x²)] dy = 0. 28. (xy² + x - 2y + 3) dx + x²y dy = 2(x + y) dy; when x ANS. (xy — 2)² + (x + 3)² = 2y² + 15. ANS. x²y + y² + 2x³ + y exp (− x²) = c. 1, y = 1. =
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