Answer Q27 & 28 showing clearly all steps 16.Given that (x – 1), (x + 1), C + 7) are consecutive terms of a geometric progression, thenthe common ratio of the progression isВ. 3A. -3C. -1D. 217.The second and fifth terms of a geometric progression are 1 and 1/27 respectively. Thearン!ar4arcommon ratio of the progression is:B. - D. -1A. 39.3.218.If (x-1), (x+1), (x+7) are consecutive terms of a geometric sequence, then x=A. -5 B. 2XC. 1 D. 319.The first term of a convergent geometric series is ß and its sum to infinity is 6B, the commonratio of the series isB. E1C.D.6.A.В.620.Given that (x - 3), (x + 3), (2x + 1) are in a geometric progression the common ratio of theprogression is:3A.В.3C. 12D. 621.The two geometric means between 8 and 64 are:80 136C.3 3D. 32, 36A. 16, 32B. 16, 2422.If 4, m, 9 are in a geometric sequence and 4, m, n are in an arithmetic sequence thhen:A. m = 3, n = 4 B. m 4, n= 8C. m = -6, n = -16 0. m = 6, n = 823.The sum to infinity of a geometric progression is 2. Given that the first term of thisprogression is 3, the fifth term isB. -D.--31C.16321624.The sum of the first three terms of a geometric progression is 14. If the first term is 2 thenthe value(s) of the common ratio is (are)A. 2В. 2. 3C. -2, 3D. -3, 225.2+1++...+ 1/16 =.39В.6363С.D.2163226.1f 1-2+4+ ...+ (-1)"+12"-1=-85 then n3=A. 10В. 12С.8D. 1527.1-() is the sum of the first n terms of a series. The 4th term of the series is:A. 16C.-15D.16B.-81628.An example of a series which possesses a sum to infinity is:A. Un= cosNI3.B.1++ 2+.2.273С.2.6.C.+3.D.2748.-...1664

Question

Answer Q27 & 28 showing clearly all steps 16.Given that (x – 1), (x + 1), C + 7) are consecutive terms of a geometric progression, thenthe common ratio of the progression isВ. 3A. -3C. -1D. 217.The second and fifth terms of a geometric progression are 1 and 1/27 respectively. Thearン!ar4arcommon ratio of the progression is:B. - D. -1A. 39.3.218.If (x-1), (x+1), (x+7) are consecutive terms of a geometric sequence, then x=A. -5 B. 2XC. 1 D. 319.The first term of a convergent geometric series is ß and its sum to infinity is 6B, the commonratio of the series isB. E1C.D.6.A.В.620.Given that (x - 3), (x + 3), (2x + 1) are in a geometric progression the common ratio of theprogression is:3A.В.3C. 12D. 621.The two geometric means between 8 and 64 are:80 136C.3 3D. 32, 36A. 16, 32B. 16, 2422.If 4, m, 9 are in a geometric sequence and 4, m, n are in an arithmetic sequence thhen:A. m = 3, n = 4 B. m 4, n= 8C. m = -6, n = -16 0. m = 6, n = 823.The sum to infinity of a geometric progression is 2. Given that the first term of thisprogression is 3, the fifth term isB. -D.--31C.16321624.The sum of the first three terms of a geometric progression is 14. If the first term is 2 thenthe value(s) of the common ratio is (are)A. 2В. 2. 3C. -2, 3D. -3, 225.2+1++...+ 1/16 =.39В.6363С.D.2163226.1f 1-2+4+ ...+ (-1)&#34;+12&#34;-1=-85 then n3=A. 10В. 12С.8D. 1527.1-() is the sum of the first n terms of a series. The 4th term of the series is:A. 16C.-15D.16B.-81628.An example of a series which possesses a sum to infinity is:A. Un= cosNI3.B.1++ 2+.2.273С.2.6.C.+3.D.2748.-...1664

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27.1-) is the sum of the first n terms of a series. The 4" term of the series is: A. 16 B.-8 C.- 15 16 16