Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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27. Which of the following statements best explains the prevalence and geographic distribution of sickle cell anemia allele (HbS).
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The homozygotes for normal hemoglobin protein are always at an advantage in all environments. |
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Homozygous recessive individuals are selected for in malarial environments. |
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Heterozygous individuals are at a selective advantage in malarial environments. |
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Sickle cell anemia is found in high frequencies only among West Africans and their descendants. |
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none of the above. |
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- In a hypothetical population, 16% have sickle-cell anemia. The population is in Hardy-Weinberg equilibrium. ( sickle-cell anemia is recessive) What is the frequency of the allele for sickle-cell anemia? What is the frequency of the allele for normal hemoglobin?arrow_forwardWhat is the selective factor, or selective environment, which allows carriers of the sickle-cell allele to have higher fitness than other genotypes? Group of answer choices A-Africa B-sickle-cell disease C-AIDS D-malariaarrow_forward21arrow_forward
- What is the heterozygous advantage of people having sickle-cell trait in areas where malaria is a major cause of death?arrow_forward4. In a region of Africa, where malaria is prevalent, 40% of the population are found to have sickle-cell anemia. The disease is caused by an abnormal hemoglobin that is found in both homozygotes (S2S2) and heterozygotes (S1S2). Many homozygotes (S2S2) suffer from anemia and often die. Heterozygotes (S1S2) incur a much less debilitating malady called "sickling trait". Approximately 3% of the people with abnormal hemoglobin are homozygotes (1.2\% of the entire population). The fitness of the S2S2 homozygotes is only 1/4 that of the heterozygotes. Where malaria is prevalent, heterozygotes exhibit overdominance with respect to fitness. If we assume that the above population is at an equilibrium frequency for the allele causing sickle-cell anemia (S2), calculate the relative fitness of the S1S1 homozygotes (which have normal hemoglobin).arrow_forwardBelow is a pedigree for a family into which Individual III-4 has married. He and his spouse, Individual III-3, are visiting a genetic counselor because they are expecting a baby (Individual IV-1). They want to know the chance that the baby will get the autosomal recessive genetic disease seen in Individual II-2. Overall, in the population, the disease is known to affect 1 in 625 individuals in the population to which this family belongs [assume this frequency is the result of random mating so represents f(aa)] I. II. E III. IV. 1 1 2 2 3 1 3 1 4 2 4 5arrow_forward
- 2arrow_forwardIs the heritability of human skin color in a particualr city greater in the summer? Please explain whyarrow_forwardSickle cell anemia is a genetic disease most common in those of African ancestry that results from the mutation of a single basepair. This mutation results in a change to the hemoglobin protein. In this experiment, “S” will represent the normal allele and “s” thesickle allele. They are codominant alleles. Therefore, SS is normal, Ss is not fatal but mildly symptomatic, and ss is debilitating,painful, and often fatal. After hundreds or even thousands of generations, both alleles are still common in those of African ancestry. How would you explain this?arrow_forward
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