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solve question 27 with complete explanation within 15-30 mins and get multiple upvotes
![25. A proton is accelerated by a potential difference of 7.20 x 10? V. What is the change in kinetic energy of
the proton? [1.15 x 1016 J]
26. An alpha particle gains 1.50 x 1015 J of kinetic energy. Through what potential difference was it
accelerated? [4.69 x 10³ V]
27. The electric field strength between two parallel plates is 9.3 x 10² v/m when the plates are 7.0 cm
apart. What would the electric field strength be if the plates were 5.0 cm apart? [1.3 x 103 V/m]
28. An electron is released from rest adjacent to the negative plate in a parallel plate apparatus. A
potential difference of 500 V is maintained between the plates, and they are in a vacuum. With what
speed does the electron collide with the positive plate? (1.3 x 10? m/s)](https://content.bartleby.com/qna-images/question/2415f85d-b35f-44ae-903c-9a2c0c36f1b8/bdb459c8-ae65-4353-8a6e-df25119402cd/g4o2v9d_processed.png)
Transcribed Image Text:25. A proton is accelerated by a potential difference of 7.20 x 10? V. What is the change in kinetic energy of
the proton? [1.15 x 1016 J]
26. An alpha particle gains 1.50 x 1015 J of kinetic energy. Through what potential difference was it
accelerated? [4.69 x 10³ V]
27. The electric field strength between two parallel plates is 9.3 x 10² v/m when the plates are 7.0 cm
apart. What would the electric field strength be if the plates were 5.0 cm apart? [1.3 x 103 V/m]
28. An electron is released from rest adjacent to the negative plate in a parallel plate apparatus. A
potential difference of 500 V is maintained between the plates, and they are in a vacuum. With what
speed does the electron collide with the positive plate? (1.3 x 10? m/s)
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