26 )The following processes are submitted to an operating system. which require no input/output (i.e. they are always ready to utilize the CPU) 1. Draw Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, Preemptive and non preemptive SJF, preemptive and nonpreemptive priority, Highest response ratio next (HRRN), and RR (quantum-2). 2. What is the average turnaround time average waiting time, schedule length, and throughput of each process for each of the scheduling algorithms in part 1? 3. Which of the algorithms results in the minimum average waiting time (over all processes)? ( 1. FCFS PID AT BT CT TAT WT P1 0 S P2 2 6 P3 2 1 P4 1 9 P5 3 3 Gantt Chart: . 2. Non-Preemptive SJF PID PI P2 P3 P4 P5 . AT BT CT TAT 0 8 6 1 9 3 Gantt Chart: Pl P2 P3 2 2 3. Preemptive SJF PID AT . 1 3 BT CT TAT 0 S 2 6 1 2 P4 1 9 P5 3 3 Gantt Chart: WT WT . . . . . . Average Turnaround Time- Average Waiting time = ScheduleLength Throughtput- Average Turnaround Time= Average Waiting time- Schedule Length= Throughput Average Turnaround Time Average Waiting time- Schedule Length= Throughtpat-

26 )The following processes are submitted to an operating system. which require no input/output (i.e. they are always ready to utilize the CPU) 1. Draw Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, Preemptive and non preemptive SJF, preemptive and nonpreemptive priority, Highest response ratio next (HRRN), and RR (quantum-2). 2. What is the average turnaround time average waiting time, schedule length, and throughput of each process for each of the scheduling algorithms in part 1? 3. Which of the algorithms results in the minimum average waiting time (over all processes)? ( 1. FCFS PID AT BT CT TAT WT P1 0 S P2 2 6 P3 2 1 P4 1 9 P5 3 3 Gantt Chart: . 2. Non-Preemptive SJF PID PI P2 P3 P4 P5 . AT BT CT TAT 0 8 6 1 9 3 Gantt Chart: Pl P2 P3 2 2 3. Preemptive SJF PID AT . 1 3 BT CT TAT 0 S 2 6 1 2 P4 1 9 P5 3 3 Gantt Chart: WT WT . . . . . . Average Turnaround Time- Average Waiting time = ScheduleLength Throughtput- Average Turnaround Time= Average Waiting time- Schedule Length= Throughput Average Turnaround Time Average Waiting time- Schedule Length= Throughtpat-

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Description: Send original answer, do not copy anything, otherwize will give multiple dislikes. Q6 )The following processes are submitted to an operating system. They are calculation processeswhich require no input/output (i.e. they are always ready to utilize th

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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