25. Consider the curve defined by the equation below and a point (2, 1) on the curve. What is the equation of the tangent line at the point (2, 1)? x? - 3y = 1 4х — Зу- 5 %3D 0 4x – 3y + 2 = 0 2х — 3у - 1 %3 0 4х — 3у + 5 %3 0 |

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
25. Consider the curve defined by the equation below and a point (2, 1) on the curve. What is the
equation of the tangent line at the point (2, 1)?
x? - 3y = 1
4х — Зу- 5 %3D 0
4x – 3y + 2 = 0
2х — 3у - 1 %3 0
4х — 3у + 5 %3 0
|
Transcribed Image Text:25. Consider the curve defined by the equation below and a point (2, 1) on the curve. What is the equation of the tangent line at the point (2, 1)? x? - 3y = 1 4х — Зу- 5 %3D 0 4x – 3y + 2 = 0 2х — 3у - 1 %3 0 4х — 3у + 5 %3 0 |
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