MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
expand_more
expand_more
format_list_bulleted
Related questions
Concept explainers
Question
![### Determining the 95% Confidence Interval for Mean Weight of Packages
In this example, we have 25 packages that are randomly selected from packages received by a parcel service. The sample has a mean weight of 21.7 pounds. Assume that the standard deviation (σ) is 2.8 pounds.
**Question:**
What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service?
### Multiple Choice Options:
- \( \boxed{X} \) \( 20.6 \text{ to } 22.8 \text{ pounds} \)
- \( \boxed{} \) \( 20.2 \text{ to } 23.2 \text{ pounds} \)
- \( \boxed{} \) \( 20.7 \text{ to } 22.7 \text{ pounds} \)
- \( \boxed{} \) \( 20.8 \text{ to } 22.6 \text{ pounds} \)
To determine the correct confidence interval, we need to use the formula for the confidence interval for the mean, given by:
\[ \bar{x} \pm Z \left( \frac{\sigma}{\sqrt{n}} \right) \]
Where:
- \( \bar{x} \) is the sample mean
- \( σ \) is the population standard deviation
- \( n \) is the sample size
- \( Z \) is the Z-value from the standard normal distribution for the desired confidence level (for 95%, Z ≈ 1.96)](https://content.bartleby.com/qna-images/question/02edcb37-a5b4-4ad7-814d-fe9fafc40457/7a15d284-f6d4-4b8f-a7a7-872409a24a98/z7dbrao_processed.jpeg)
Transcribed Image Text:### Determining the 95% Confidence Interval for Mean Weight of Packages
In this example, we have 25 packages that are randomly selected from packages received by a parcel service. The sample has a mean weight of 21.7 pounds. Assume that the standard deviation (σ) is 2.8 pounds.
**Question:**
What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service?
### Multiple Choice Options:
- \( \boxed{X} \) \( 20.6 \text{ to } 22.8 \text{ pounds} \)
- \( \boxed{} \) \( 20.2 \text{ to } 23.2 \text{ pounds} \)
- \( \boxed{} \) \( 20.7 \text{ to } 22.7 \text{ pounds} \)
- \( \boxed{} \) \( 20.8 \text{ to } 22.6 \text{ pounds} \)
To determine the correct confidence interval, we need to use the formula for the confidence interval for the mean, given by:
\[ \bar{x} \pm Z \left( \frac{\sigma}{\sqrt{n}} \right) \]
Where:
- \( \bar{x} \) is the sample mean
- \( σ \) is the population standard deviation
- \( n \) is the sample size
- \( Z \) is the Z-value from the standard normal distribution for the desired confidence level (for 95%, Z ≈ 1.96)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 4.2 minutes. The population standard deviation is known to be 0.6 minute. We want to test to determine whether or not the mean waiting time of all customers is significantly more than 4 minutes. The test statistic is O a. 5.56 O b. 0.33 O c. 2.58 O d. 3.33arrow_forwardConstruct a confidence interval for the ratio of the population variances given the following sample statistics. Round your answers to four decimal places. n1=9, n2=18, s1^2/s2^2=1.17, a=0.1arrow_forward2. A sample of six college basketball player had an average weight of 217 pounds with a sample standard deviation of 10 pounds. Find the 95% confidence interval of the true mean weight of all basketball player.arrow_forward
- 31 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 15.6 pounds. Assume that stdv = 2.2 pounds. What is the 95% confidence interval for the true mean weight, u, of all packages received by the parcel service?arrow_forwardPlease answer all. Thank you. A national random sample of 20 NCAE Scores from 2010 is listed below. 29,26,13,23,23,25,17,22,17,19 12,26,30,30,18,14,12,26,17,18 Calculate the 95 percent confidence interval for the mean NCAE score if the sample standard deviation is about 5.9407. A.) between 18.22 and 23.48 B.) between 18.07 and 23.63 C.) between negative infinity and 23.15 D.) between negative infinity and 23.05 The value of z selected for constructing a given confidence interval is called A.) confidence B.) error C.) student D.) critical valuearrow_forwarddo B AND Carrow_forward
- A study of 4 bolts of carpet showed that their average length was 76.2 yards and the sample standard deviation was 5.6 yards. Which of the following is the 80% confidence interval for the mean length per bolt of carpet? O A. 75.8 to 76.6 O B. 72.62 to 79.78 O C. 71.61 to 80.79 D. 75.40 to 77.00arrow_forwardA survey of 73 randomly selected homeowners finds that they spend a mean of $74 per month on home maintenance. Construct a 95% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners. Assume that the population standard deviation is $16 per month. Round to the nearest cent.arrow_forwardA local university administers a comprehensive examination to the candidates for B.S. degrees in Business Administration. Five examinations are selected at random and scored. The scores are shown below. Develop a 95% confidence interval estimate for the mean of the population. Assume the population is normally distributed. Grades 80 90 91 62 77 Select one: O a. 65.39 - 94.61 O b. 68.78 - 91.22 О с. O d. 67.52 - 92.48 69.48 - 90.52arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
Probability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage Learning
Statistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning 
Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSON
The Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. Freeman
Introduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman