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242 Is A2 102 82 150 E = 39.42 V Problem 6: (b) What is I! Answer: I = 3.0 A. (c) What is I2? Answer: I2 = 1.71 A. (d) What is I3? Answer: I3 = 1.29 A. (c) What is I4? Answer: I4 = 0.43 A. (f) What is I5? Answer: I, = 1.28 A. (g) What is I6? Answer: I6 = 0.77 A. (h) What is I-? Answer: I7 = 0.52 A. (a) What is Reg? Answer: Reg= 13.14 N.

242 Is A2 102 82 150 E = 39.42 V Problem 6: (b) What is I! Answer: I = 3.0 A. (c) What is I2? Answer: I2 = 1.71 A. (d) What is I3? Answer: I3 = 1.29 A. (c) What is I4? Answer: I4 = 0.43 A. (f) What is I5? Answer: I, = 1.28 A. (g) What is I6? Answer: I6 = 0.77 A. (h) What is I-? Answer: I7 = 0.52 A. (a) What is Reg? Answer: Reg= 13.14 N.

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### Circuit Analysis Problem #### Circuit Diagram The circuit features several resistors and a voltage source: - Resistors with values: 3Ω, 5Ω, 6Ω, 8Ω, 10Ω, 15Ω, and 24Ω. - Voltage source: \( \varepsilon = 39.42 \, \text{V} \). #### Current Paths - \( I_1 \): Leaves the voltage source, moving through 3Ω and 5Ω resistors. - \( I_2 \): Flows through the left branch with 3Ω, 10Ω, and 15Ω resistors. - \( I_3 \): Travels through the 6Ω resistor. - \( I_4 \) and \( I_5 \): Pass through the right branch with 24Ω and 8Ω resistors. - \( I_6 \) and \( I_7 \): Flow through the middle branch with 10Ω and 15Ω resistors. ### Problem 6: Current and Resistance Calculation #### Solutions - (a) What is \( R_{\text{eq}} \)? **Answer:** \( R_{\text{eq}} = 13.14 \, \Omega \). - (b) What is \( I_1 \)? **Answer:** \( I_1 = 3.0 \, \text{A} \). - (c) What is \( I_2 \)? **Answer:** \( I_2 = 1.71 \, \text{A} \). - (d) What is \( I_3 \)? **Answer:** \( I_3 = 1.29 \, \text{A} \). - (e) What is \( I_4 \)? **Answer:** \( I_4 = 0.43 \, \text{A} \). - (f) What is \( I_5 \)? **Answer:** \( I_5 = 1.28 \, \text{A} \). - (g) What is \( I_6 \)? **Answer:** \( I_6 = 0.77 \, \text{A} \). - (h) What is \( I_7 \)? **Answer:** \( I_7 = 0.52 \, \text
Transcribed Image Text:### Circuit Analysis Problem #### Circuit Diagram The circuit features several resistors and a voltage source: - Resistors with values: 3Ω, 5Ω, 6Ω, 8Ω, 10Ω, 15Ω, and 24Ω. - Voltage source: \( \varepsilon = 39.42 \, \text{V} \). #### Current Paths - \( I_1 \): Leaves the voltage source, moving through 3Ω and 5Ω resistors. - \( I_2 \): Flows through the left branch with 3Ω, 10Ω, and 15Ω resistors. - \( I_3 \): Travels through the 6Ω resistor. - \( I_4 \) and \( I_5 \): Pass through the right branch with 24Ω and 8Ω resistors. - \( I_6 \) and \( I_7 \): Flow through the middle branch with 10Ω and 15Ω resistors. ### Problem 6: Current and Resistance Calculation #### Solutions - (a) What is \( R_{\text{eq}} \)? **Answer:** \( R_{\text{eq}} = 13.14 \, \Omega \). - (b) What is \( I_1 \)? **Answer:** \( I_1 = 3.0 \, \text{A} \). - (c) What is \( I_2 \)? **Answer:** \( I_2 = 1.71 \, \text{A} \). - (d) What is \( I_3 \)? **Answer:** \( I_3 = 1.29 \, \text{A} \). - (e) What is \( I_4 \)? **Answer:** \( I_4 = 0.43 \, \text{A} \). - (f) What is \( I_5 \)? **Answer:** \( I_5 = 1.28 \, \text{A} \). - (g) What is \( I_6 \)? **Answer:** \( I_6 = 0.77 \, \text{A} \). - (h) What is \( I_7 \)? **Answer:** \( I_7 = 0.52 \, \text
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