24.34   A parallel-plate capacitor has capacitance C₀ = 8.00 pF when there is air between the plates. The separation between the plates is 1.50 mm.   (a) What is the maximum magnitude of charge Q that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 x 10⁴ V/m?   (b) A dielectric with K = 2.70 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00 x 10⁴ V/m?

(1 An object moves along a straight track from the point (-2,-1, 2) to the point (-3, -6, 7). The only force acting on it is a constant F = -2i+3j + 5k newtons. Find the work done if the distance is measured in meters. Work = joules.

A parallel-plate capacitor has square plates that are 7.60 cm on each side and 4.00 mm apart. The space between the plates is completely filled with two square slabs of dielectric, each 7.60 cm on a side and 2.00 mm thick. One slab is Pyrex glass and the other slab is polystyrene. If the potential difference between the plates is 88.0 V, find how much electrical energy (in nJ) can be stored in this capacitor. 16.5662 × nj

A parallel-plate capacitor has plates separated by 0.58 mm. What is the potential difference between the plates if the electric field between the two plates has a magnitude of 3.2 104 V/m?   Group of answer choices 101 V 18.6 V 92.8 V 165 V

A charged capacitor consisting of two parallel plates has an area and separate of 0.500 m2 and 9.00 mm respectively. If the electric field strength between the plates is 3.0 x 106 Vm-1, calculate the energy stored in the capacitor.

A parallel-plate capacitor with area 0.220 m² and plate separation of 2.00 mm is connected to a 7.40-V battery. (a) What is the capacitance? F (b) How much charge is stored on the plates? C (c) What is the electric field between the plates? N/C (d) Find the magnitude of the charge density on each plate. C/m2 (e) Without disconnecting the battery, the plates are moved farther apart. Qualitatively, what happens to each of the previous answers?

(a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 6.00 cm²? (Assume air has a dielectric strength of 3.00 x 106 V/m and dielectric constant of 1.00.) nC (b) Find the maximum charge if nylon is used between the plates instead of air. (Assume nylon has a dielectric strength of 14.0 × 106 V/m and dielectric constant of 3.4.) nC

Consider a parallel-plate capacitor whose (circular) plates are separated by a 3.0-mm-thick slab of glass with dielectric constant 5.0. The diameter of each plate is 4.0 cm, and the slab fills the entire volume between the plates. The electric field between the plates with the dielectric in place has magnitude 8.0 x 103 V/m. (a) Find the magnitude of the charge on either plate of the capacitor. (b) Now suppose the slab of glass is removed, leaving an air gap between the plates. Calculate the total energy stored in this capacitor and the energy density (energy per unit volume).

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.90 mm. A 15.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates.kV/m(b) Calculate the surface charge density.nC/m2(c) Calculate the capacitance.pF(d) Calculate the charge on each plate.pC

A parallel-plate capacitor consists of two plates, each with an area of 25  cm2 separated by 3.0  mm . The charge on the capacitor is 4.8  nC . A proton is released from rest next to the positive plate. How long does it take for the proton to reach the negative plate? Express your answer with the appropriate units.