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24. Work Find the work done when F = 300i + 400j is applied to an object that moves along the vector D = 10i - 2j, where units are in pounds and feet. Find the magnitude of F and interpret the result.

24. Work Find the work done when F = 300i + 400j is applied to an object that moves along the vector D = 10i - 2j, where units are in pounds and feet. Find the magnitude of F and interpret the result.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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i need to know if i got this right my answer was 2200 and magnitude was 400 please explain if i got this wrong

**Exercise 24: Work Calculation** **Problem Statement:** Find the work done when a force \( \mathbf{F} = 300\mathbf{i} + 400\mathbf{j} \) is applied to an object that moves along the vector \( \mathbf{D} = 10\mathbf{i} - 2\mathbf{j} \), where the units are in pounds and feet. **Tasks:** 1. Calculate the work done. 2. Find the magnitude of the force \( \mathbf{F} \). 3. Interpret the result. **Analysis:** - **Work Done:** Calculate using the dot product of the force vector \( \mathbf{F} \) and the displacement vector \( \mathbf{D} \). - **Magnitude of \( \mathbf{F} \):** Found using the formula \( \sqrt{(300)^2 + (400)^2} \). Note: Ensure that the calculations adhere to the proper units and provide an explanation of the physical meaning of the results.
Transcribed Image Text:**Exercise 24: Work Calculation** **Problem Statement:** Find the work done when a force \( \mathbf{F} = 300\mathbf{i} + 400\mathbf{j} \) is applied to an object that moves along the vector \( \mathbf{D} = 10\mathbf{i} - 2\mathbf{j} \), where the units are in pounds and feet. **Tasks:** 1. Calculate the work done. 2. Find the magnitude of the force \( \mathbf{F} \). 3. Interpret the result. **Analysis:** - **Work Done:** Calculate using the dot product of the force vector \( \mathbf{F} \) and the displacement vector \( \mathbf{D} \). - **Magnitude of \( \mathbf{F} \):** Found using the formula \( \sqrt{(300)^2 + (400)^2} \). Note: Ensure that the calculations adhere to the proper units and provide an explanation of the physical meaning of the results.
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