Do 24 and 25 5:27 41 SearchFI Generation CrossF2 Generation (at least 500 flies)Fl red-eyed females x white-eyed males 50% of females are red-eyed and 50% are white-eyed50% of males are red-eyed and 50% are white-eyed21. The best explanation for the red-eyed F1 females is(A) mutation(B) culture contamination(C) dominance(D) multiple loci(E) sex-influenced traits22. There are white-eyed females in the F2 generation because(A) white is a dominant allele(B) the white allele is autosomal(C) a mutation has occurred(D) these F2 females have two white alleles(E) the white allele is located on the Y chromosome23. Which of the following best describes the mode of inheritance of eye color in the whiteculture?(A) Autosomal(B) Dominant(C) Located on the Y chromosome(D) Sex-linked(E) Lethal24. Assume that genes A and B are not linked. If the probability of allele A in a gamete is 1/2and the probability of allele B in a gamete is 1/2, then the probability that both A and Bare in the same gamete is(A) 1/2 x 1/2(B) 1/2 + 1/2(C) 1/2 1/2(D) 1/2(E) 1/2 x 1/225. A couple has 5 children, all sons. If the woman gives birth to a sixth child, what is theprobability that the sixth child will be a son?(A) 5/6(В) 1/2(С) 1/5(D) 1/6(E) 1/64

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Description: Do 24 and 25 5:27 41 SearchFI Generation CrossF2 Generation (at least 500 flies)Fl red-eyed females x white-eyed males 50% of females are red-eyed and 50% are white-eyed50% of males are red-eyed and 50% are white-eyed21. The best explanation for the

Human beings contain 23 pairs of chromosomes out of which 22 pairs are autosomes and one pair are…

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24. Assume that genes A and B are not linked. If the probability of allele A in a gamete is 1/2 and the probability of allele B in a gamete is 1/2, then the probability that both A and B are in the same gamete is (A) 1/2 x 1/2 (B) 1/2 + 1/2 (C) 1/2 1/2 (D) 1/2 (E) 1/2 x 1/2 25. A couple has 5 children, all sons. If the woman gives birth to a sixth child, what is the probability that the sixth child will be a son? (A) 5/6 (B) 1/2 (C) 1/5 (D) 1/6 (E) 1/64

24. Assume that genes A and B are not linked. If the probability of allele A in a gamete is 1/2 and the probability of allele B in a gamete is 1/2, then the probability that both A and B are in the same gamete is (A) 1/2 x 1/2 (B) 1/2 + 1/2 (C) 1/2 1/2 (D) 1/2 (E) 1/2 x 1/2 25. A couple has 5 children, all sons. If the woman gives birth to a sixth child, what is the probability that the sixth child will be a son? (A) 5/6 (B) 1/2 (C) 1/5 (D) 1/6 (E) 1/64

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter14: Chromosomes And Human Inheritance

Section: Chapter Questions

Problem 5GP: Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With...

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F1 Generation Cross F2 Generation (at least 500 flies) Fl red-eyed females x white-eyed males 50% of females are red-eyed and 50% are white- eyed 50% of males are red-eyed and 50% are white-eyed 21. The best explanation for the red-eyed F1 females is (A) mutation (B) culture contamination (C) dominance (D) multiple loci (E) sex-influenced traits 22. There are white-eyed females in the F2 generation because (A) white is a dominant allele (B) the white allele is autosomal (C) a mutation has occurred (D) these F2 females have two white alleles (E) the white allele is located on the Y chromosome 23. Which of the following best describes the mode of inheritance of eye color in the white culture? (A) Autosomal (B) Dominant (C) Located on the Y chromosome (D) Sex-linked (E) Lethal 24. Assume that genes A and B are not linked. If the probability of allele A in a gamete is 1/2 and the probability of allele B in a gamete is 1/2, then the probability that both A and B are in the same gamete is…
You conduct a cross in Drosophila that produces only half as many male as female offspring. What might you suspect as a cause?
How would you perform a reciprocal cross for the characteristic of stem height in the garden pea?
Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X chromosome alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an allele on an X chromosome, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X chromosome allele, how many types or gametes can she produce with respect to that allele?
Why is it more efficient to perform a test cross with a homozygous recessive donor than a homozygous dominant donor? How could the same information still he found with a homozygous dominant donor?
The gene for flower position in pea plants exists as axial or terminal alleles. Given that axial is dominant to terminal, list all of the possible F1 and F2 genotypes and phenotypes from a cross involving parents that are homozygous for each trait. Express genotypes with conventional genetic abbreviations.
Figure 7.2 If a mutation occurs so that a fungus is no longer able to produce a minus mating type, will it still be able to reproduce? Figure 7.2 (a) In animals, sexually reproducing adults form haploid gametes from diploid germ cells. (b) Fungi, such as black bread mold (Rhizopus nigricans), have haploid-dominant life cycles. (c) Plants have a life cycle that alternates between a multicellular haploid organism and a multicellular diploid organism. (credit c fern: modification of work by Cory Zanker; credit c gametophyte: modification of work by Vlmastra/Wikimedia Commons)
In Drosophila, two genes, one for body color and one for eye color, are carried on the same chromosome. The wild-type gray body color is dominant to black body color, and wild-type red eyes are dominant to purple eyes. You make a cross between a fly with gray body and red eyes and a fly with black body and purple eyes. Among the offspring, about half have gray bodies and red eyes and half have black bodies and purple eyes. A small percentage have: (a) black bodies and red eyes; or (b) gray bodies and purple eyes. What alleles are carried together on the chromosomes in each of the flies used in the cross? What alleles are carried together on the chromosomes of the F1 flies with black bodies and red eyes, and those with gray bodies and purple eyes?
23- In pea plants, axial flower position is dominant over terminal flower position. A student crosses a heterozygous axial flower with a plant with terminal flowers. What percentage of the plants will exhibit a homozygous genotype? a) 100% b) 0% c) 50% d) 75% 24- In pea plants, round seed is completely dominant over wrinkled seed. What genotype will result if a homozygous round seed plant is cross with a wrinkled seed plant? a. RR b. Rr c. Rr d. All of the above can be obtained
13 Black coat color (B) in cocker spaniels is dominant to white coat color (b). Solid coat pattern (S) is dominant to spotted pattern (s). The pattern arrangement is located on a different chromosome than the one for color, and its gene segregates independently of the color gene. A male that is black with a solid pattern mates with three females. Indicate the genotypes of the parents. a) The mating with female A, which is white, solid, produces four pups: two black, solid, and two white, solid. b) The mating with female B, which is black, solid, produces a single pup, which is white, spotted. c) The mating with female C, which is white, spotted, produces four pups: one white, solid; one white spotted; one black, solid; one black, spotted.
7-5. In corn a pair of genes determines leaf shape and another pair determines pollen shape. A ragged-leafed plant with round pollen was crossed to a ragged-leafed plant with angular-pollen, and the resultant progeny were classified as follows: Class Phenotypes 186 ragged-leaf round-pollen 11 IV 174 ragged-leaf angular-pollen 57 smooth-leaf round-pollen Total 63/480 smooth-leaf angular-pollen (a) Using alphabetical letters of your choice, designate the genes for the different leaf and pollen characters. (b) On the basis of the symbols given in (a) 1 provide genotypes two parents. (c) (forth)/(nbers) According to your hypothesis what would you have expected for each of the four classes of progeny? (d) After re viewing Chapter 8, use the chi-square method (p. 132) to test your hypothesis and indicate whether you accept or reject it.
16 - The phenotype of vestigial (short) wings (vg) in Drosophila melanogaster is caused by a recessive mutant gene that independently assorts with a recessive gene for hairy (h) body. Assume that a cross is made between a fly the is homozygous for normal wings with a hairy body and a fly with vestigial wings that is homozygous for normal body hair. The wild-type F1 flies were crossed among each other to produce 1024 offspring. Which phenotypes would you expect among the 1024 offspring, and how many of each phenotype would you expect? a) Phenotypes: wild, vestigial, hairy, and vestigial hairy; Numbers expected: wild (256), vestigial (256), hairy (256), and vestigial hairy (256). b) O Phenotypes: wild, vestigial, hairy, and vestigial hairy; Numbers expected: wild (576), vestigial (192), hairy (192), and vestigial hairy (64). C) O Phenotypes: wild, vestigial, hairy, and vestigial hairy; Numbers expected: wild (192), vestigial (256), hairy (64), and vestigial hairy (192). d) All vestigial…