238 U → 95 Sr+ 140 Xe + 3n 32.26 given the atomic masses to be m(238 U)= 238.050784 u, m(5 Sr)= 94.919388 u, m(140 Xe)= 139.921610 u, and m(n)= 1.008665 u.

(a) Write the complete α decay equation for 226 Ra . (b) Find the energy released in the decay.

β− decay producing 90Y . The parent nuclide is a major waste product of reactors and has chemistry similar to calcium, so that it is concentrated in bones if ingested ( 90Y is also radioactive.)

Consider the fission reaction n + 235 U After having found the missing nuclide, calculate the Q-value of the reaction. Enter your result in MeV to 1 decimal place ⁰Xe + ? + 2n. 140-

In the following Nuclear reaction, what are the unknown components? What is A and Z?

Calculate the energy released (Q value) from the following fission reaction:

12C+21Ne¹B+22Na? (The atomic mass of 3. What is the energy absorbed in this endothermic nuclear reaction 12C is 12 u, 2Ne is 20.93847 u, ¹B is 11.009305 u, and that of 22Na is 21.994436 u) 5 MeV 14 Dr.

Calculate the energy released in the following fission reaction: 232Tn + n → 99Kr +124Xe + 10n  (Express your answer to five significant figures in MeV) Recall that the atomic masses are 232Th = 232.038051 u, 99Kr = 98.957606 u, and 124Xe = 123.905894 u.

(a) Show that about 1.0 × 1010 J would be released by the fusion of the deuterons in 1.0 gal of water. Note that 1 of every 6 500 hydrogen atoms is a deuteron. (b) The average energy consumption rate of a person living in the United States is about 1.0 × 104 J/s (an average power of 10 kW). At this rate, how long would the energy needs of one person be supplied by the fusion of the deuterons in 1.0 gal of water? Assume the energy released per deuteron is 1.64 MeV